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6. The 12-Mg "jump jet" is capable of taking off vertically from the deck of a ship. If its jets exert a constant vertical force of 150 kN on the plane, determine its velocity and how high it goes in t = 6 s, starting from rest. Neglect the loss of fuel during the lift. * 150 kN v=14.96 m/s; h= 47.25 m v= 17.99 m/s; h= 46.28 m v= 15.10 m/s; h= 45.40 m v= 16.10 m/s; h= 48.40 m

6. The 12-Mg "jump jet" is capable of taking off vertically from the deck of a ship. If its jets exert a constant vertical force of 150 kN on the plane, determine its velocity and how high it goes in t = 6 s, starting from rest. Neglect the loss of fuel during the lift. * 150 kN v=14.96 m/s; h= 47.25 m v= 17.99 m/s; h= 46.28 m v= 15.10 m/s; h= 45.40 m v= 16.10 m/s; h= 48.40 m

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
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6. The 12-Mg "jump jet" is capable of taking off vertically from the deck of a ship. If its jets exert a constant vertical force of 150 kN on the plane, determine its velocity and how high it goes in t = 6 s, starting from rest. Neglect the loss of fuel during the lift. * 150 kN v=14.96 m/s; h= 47.25 m v= 17.99 m/s; h= 46.28 m v= 15.10 m/s; h= 45.40 m v= 16.10 m/s; h= 48.40 m
Transcribed Image Text:6. The 12-Mg "jump jet" is capable of taking off vertically from the deck of a ship. If its jets exert a constant vertical force of 150 kN on the plane, determine its velocity and how high it goes in t = 6 s, starting from rest. Neglect the loss of fuel during the lift. * 150 kN v=14.96 m/s; h= 47.25 m v= 17.99 m/s; h= 46.28 m v= 15.10 m/s; h= 45.40 m v= 16.10 m/s; h= 48.40 m
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