6. Show that when ) < |z - 1| < 2, e - ( - 3) (2 - 1)(2 – 3) Complex Analysis n=0 (z-1)" 2+2 2(z-1)

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6. Show that when 0</z-11 < 2,
(z-1)(z-3)
Complex Analysis
= -3
#w()
(z-1)"
2n+2
2(z-1)
Transcribed Image Text:6. Show that when 0</z-11 < 2, (z-1)(z-3) Complex Analysis = -3 #w() (z-1)" 2n+2 2(z-1)
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