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- Consider this nucleophilic substitution reaction. 1. Highlight the electrophilic carbon in red, and highlight the leaving group in blue. Highlight the atom in the nucleophile that will attack the electrophilic center in green. Only atoms need to be highlighted and not the lone pairs or formal charges. 2. Draw the product(s) of the reaction. Include all lone pairs.draw a reaction energy diagram for an exergonic rxn that is slow. in your diagram what in your diagram show your reaction is slow?Please review your answers. You say the reaction on the right is slower, then in the next question it is faster?
- Use the dropdown menu to indicate whether the rate of the reaction shown below will increase, decrease, or remain the same when the reaction conditions are changed to X or to Y or to Z (see below). NaCN Br CN CH3CN X: Change the leaving group from Br to CI Y: Increase the concentration of haloalkane Z: Increase the concentration of NaCN X: choose your answer... Y: choose your answer... Z: choose your answer... >Identify the stronger nucleophile in each pair. a.NH3, −NH2 b.CH3NH2, CH3OH c.CH3CO2−, CH3CH2O−Add curved arrows to show the forming and breaking of bonds in the reaction below. C с Ċ Add/Remove step
- This reaction is an example of conjugate addition of a nucleophile to an a,ẞ-unsaturated carbonyl. H3C LOCH3 H₂O H3C OCH3 OCH3 Draw the two resonance structures of the enolate anion intermediate for this reaction. • Draw an R1 group in place of CoA. The R group tool is located in the charges and lone pairs drop-down menu. • Draw one structure per sketcher. Add additional sketchers using the drop-down menu in the bottom right corner. Separate resonance structures using the symbol from the drop-down menu. • O H CH3 ? [FDraw the most stable resonance form for the intermediate in the following electrophilic substitution reaction.Add curved arrows to the reactants in this reaction. A double-barbed curved arrow is used to represent the movement of a pair of electrons. Draw curved arrows. Select Draw Rings More Erase | : 0 H-O: H OH