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6. page 95, A5-kg mass is connected by a string to a 4-kg mass, and the string passes over a massless frictionless pulley so that the 5-kg mass sits on a tabletop and the 4-kg mass hangs straight down. If the system is static, what must be the frictional force acting between the tabletop and the 5-kg mass? AN at equilibrium 49 N Fe= 9.8x9-88.2 N >FF Umg 5-9.8=49 N 39.2 N √mg4•9.8=39.2 N

6. page 95, A5-kg mass is connected by a string to a 4-kg mass, and the string passes over a massless frictionless pulley so that the 5-kg mass sits on a tabletop and the 4-kg mass hangs straight down. If the system is static, what must be the frictional force acting between the tabletop and the 5-kg mass? AN at equilibrium 49 N Fe= 9.8x9-88.2 N >FF Umg 5-9.8=49 N 39.2 N √mg4•9.8=39.2 N

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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### Problem Statement **6.** A 5-kg mass is connected by a string to a 4-kg mass, and the string passes over a massless frictionless pulley so that the 5-kg mass sits on a tabletop and the 4-kg mass hangs straight down. If the system is static, what must be the _frictional force_ acting between the tabletop and the 5-kg mass? ### Explanation and Calculations **Diagram:** The diagram illustrates a 5-kg mass on a tabletop connected via a string over a pulley to a hanging 4-kg mass. The forces acting on these masses include gravitational force, normal force, and frictional force. **Calculations:** 1. **Gravitational Force on 4-kg Mass:** - \( F_g = m \cdot g = 4 \, \text{kg} \times 9.8 \, \text{m/s}^2 = 39.2 \, \text{N} \) 2. **Gravitational Force on 5-kg Mass:** - \( F_g = m \cdot g = 5 \, \text{kg} \times 9.8 \, \text{m/s}^2 = 49 \, \text{N} \) 3. **Frictional Force (Static Equilibrium):** - For static equilibrium, the net force must be zero. - The frictional force \( F_f \) must balance the gravitational pull on the 4-kg mass. - \( F_f = 39.2 \, \text{N} \) **Conclusion:** The frictional force required to keep the system in static equilibrium is \( 39.2 \, \text{N} \). This explanation provides a detailed analysis of the forces involved in the problem, helping students understand how friction and gravity work together in a static system.
Transcribed Image Text:### Problem Statement **6.** A 5-kg mass is connected by a string to a 4-kg mass, and the string passes over a massless frictionless pulley so that the 5-kg mass sits on a tabletop and the 4-kg mass hangs straight down. If the system is static, what must be the _frictional force_ acting between the tabletop and the 5-kg mass? ### Explanation and Calculations **Diagram:** The diagram illustrates a 5-kg mass on a tabletop connected via a string over a pulley to a hanging 4-kg mass. The forces acting on these masses include gravitational force, normal force, and frictional force. **Calculations:** 1. **Gravitational Force on 4-kg Mass:** - \( F_g = m \cdot g = 4 \, \text{kg} \times 9.8 \, \text{m/s}^2 = 39.2 \, \text{N} \) 2. **Gravitational Force on 5-kg Mass:** - \( F_g = m \cdot g = 5 \, \text{kg} \times 9.8 \, \text{m/s}^2 = 49 \, \text{N} \) 3. **Frictional Force (Static Equilibrium):** - For static equilibrium, the net force must be zero. - The frictional force \( F_f \) must balance the gravitational pull on the 4-kg mass. - \( F_f = 39.2 \, \text{N} \) **Conclusion:** The frictional force required to keep the system in static equilibrium is \( 39.2 \, \text{N} \). This explanation provides a detailed analysis of the forces involved in the problem, helping students understand how friction and gravity work together in a static system.
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Mass on the table top = m1 = 5kg

Another mass = m2 = 4 kg

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