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6. In Fig., solve for IB, IC, and VCE. Also, construct a DC load line showing the values of IC(sat),VCE (off), Ico, and VCEQ. +Vcc = 12 V R₂ = 390 kn R = 1.5 k Boc=150

6. In Fig., solve for IB, IC, and VCE. Also, construct a DC load line showing the values of IC(sat),VCE (off), Ico, and VCEQ. +Vcc = 12 V R₂ = 390 kn R = 1.5 k Boc=150

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
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### Transistor Biasing Circuit Analysis #### Problem Statement In the figure below, solve for \( I_B \), \( I_C \), and \( V_{CE} \). Also, construct a DC load line showing the values of \( I_{C(sat)} \), \( V_{CE(off)} \), \( I_{CQ} \), and \( V_{CEQ} \). #### Circuit Diagram The given circuit diagram is as follows: - The supply voltage \( V_{CC} \) is 12 V. - The base resistor \( R_B \) is 390 kΩ. - The collector resistor \( R_C \) is 1.5 kΩ. - The current gain \( \beta_{DC} \) is 150. ![Transistor Circuit](#) (Note: Insert the image of the transistor circuit here) #### Step-by-Step Solution 1. **Solve for \( I_B \) (Base Current):** Using the formula for base current, \[ I_B = \frac{V_{CC} - V_{BE}}{R_B + (\beta_{DC} \cdot R_E)} \] Assuming \( V_{BE} \approx 0.7V \) (typical for silicon transistors), \[ I_B = \frac{12V - 0.7V}{390k\Omega} \approx \frac{11.3V}{390k\Omega} \approx 29 \mu A \] 2. **Solve for \( I_C \) (Collector Current):** Using the current gain relationship, \[ I_C = \beta_{DC} \cdot I_B \] \[ I_C = 150 \cdot 29 \mu A \approx 4.35 mA \] 3. **Solve for \( V_{CE} \) (Collector-Emitter Voltage):** Using the formula for \( V_{CE} \), \[ V_{CE} = V_{CC} - (I_C \cdot R_C) \] \[ V_{CE} = 12V - (4.35mA \cdot 1.5k\Omega) \approx 12V - 6.525V \approx 5.475V \] ####
Transcribed Image Text:### Transistor Biasing Circuit Analysis #### Problem Statement In the figure below, solve for \( I_B \), \( I_C \), and \( V_{CE} \). Also, construct a DC load line showing the values of \( I_{C(sat)} \), \( V_{CE(off)} \), \( I_{CQ} \), and \( V_{CEQ} \). #### Circuit Diagram The given circuit diagram is as follows: - The supply voltage \( V_{CC} \) is 12 V. - The base resistor \( R_B \) is 390 kΩ. - The collector resistor \( R_C \) is 1.5 kΩ. - The current gain \( \beta_{DC} \) is 150. ![Transistor Circuit](#) (Note: Insert the image of the transistor circuit here) #### Step-by-Step Solution 1. **Solve for \( I_B \) (Base Current):** Using the formula for base current, \[ I_B = \frac{V_{CC} - V_{BE}}{R_B + (\beta_{DC} \cdot R_E)} \] Assuming \( V_{BE} \approx 0.7V \) (typical for silicon transistors), \[ I_B = \frac{12V - 0.7V}{390k\Omega} \approx \frac{11.3V}{390k\Omega} \approx 29 \mu A \] 2. **Solve for \( I_C \) (Collector Current):** Using the current gain relationship, \[ I_C = \beta_{DC} \cdot I_B \] \[ I_C = 150 \cdot 29 \mu A \approx 4.35 mA \] 3. **Solve for \( V_{CE} \) (Collector-Emitter Voltage):** Using the formula for \( V_{CE} \), \[ V_{CE} = V_{CC} - (I_C \cdot R_C) \] \[ V_{CE} = 12V - (4.35mA \cdot 1.5k\Omega) \approx 12V - 6.525V \approx 5.475V \] ####
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