6. In analyzing coal samples for ash content,threetwoofcruciblesandtypestemperatures were usedfactorial arrangement.in a completeCrucibleTemperatureSteelSilica8258.77.29.39.18759.49.69.79.892510.110.210.410.7Perform an ANOVA, conducting appropriatetests at the 5% significance level. Does thereappear to be a difference between the twotypes of crucible with respect to average ashcontent?

There are two variables which are Temperature and Crucible. Row variable is Temperature and Column…

Answered: 6. In analyzing coal samples for ash…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A particular fruit's weights are normally distributed, with a mean of 492 grams and a standard deviation of 14 grams. If you pick one fruit at random, what is the probability that it will weigh between 479 grams and 511 grams
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Is the Diet Practical? When 40 people used the Weight Watchers diet for one year, their mean weight loss was 3.0 lb and the standard deviation was 4.9 lb (based on data from “Comparison of the Atkins, Ornish, Weight Watchers, and Zone Diets for Weight Loss and Heart Disease Reduction, ” by Dansinger et al., Journal of the American Medical Association, Vol. 293, No. 1). Use a 0.01 significance level to test the claim that the mean weight loss is greater than 0. Based on these results, does the diet appear to be effective? Does the diet appear to have practical significance?
4. Answer the following. Feel free to use the Excel Demo from the course website called "alpha and beta". a. What happens to the probability of type IlI error as the difference between mu_0 and the actual mean increases? b. What happens to the probability of type II error as the sample size increases? C. How does changing the significance level effect the type Il error probability? -Accessibility: Good to go O Focus a AP hp
The mean salary of federal government employees on the General Schedule is $62,493. The average salary of 21 state employees who do similar work is $60,800 with a population standard deviation of $2,700. At the .01 significance level, can it be concluded that state employees earn on average less than federal employees?
In an effort to determine which company between Primacom Outsourcing Company and Technica Global Services has better customer service, an independent survey group gathered data on the length of time (in minutes) a customer has to wait on hold before someone answers the phone when calling the customer care hotline for assistance. The data is summarized below. Statistics Primacom Outsourcing Company Technica Global Services Mean 8.14 9.426 Standard Deviation 1.345 1.813 Sample Size 7 7 Is there a significant difference between the average lengths of time customers are on hold for the two companies? Use a 5% level of significance. Assume that the lengths of time on hold are normally distributed with unknown but equal population variances. A. Perform a complete test of hypothesis. B. Select here the conclusion for this test of hypothesis. There is a significant difference between the average lengths of time customers are on hold for the two companies. There is no significant difference…
Run a single proportion test. Significance level= 0.05
The void volume within a textile fabric affects comfort, flammability, and insulation properties. Permeability of a fabric refers to the accessibility of void space to the flow of a gas or liquid. An article gave summary information on air permeability (cm3/cm2/sec) for a number of different fabric types. Consider the following data on two different types of plain-weave fabric: Fabric Type Sample Size Sample Mean Sample Standard Deviation Cotton 10 51.41 0.75 Triacetate 10 132.15 3.59 Assuming that the porosity distributions for both types of fabric are normal, let's calculate a confidence interval for the difference between true average porosity for the cotton fabric and that for the acetate fabric, using a 95% confidence level. Before the appropriate t critical value can be selected, df must be determined: df = 0.5625 10 + 12.8881 10 2 (0.5625/10)2 9 + (12.8881/10)2 9 = 1.8092 0.1849…
Report an appropriate hypothesis test and use a 5% significance level. The alternative hypothesis for the One-way Anova F-test would be Group of answer choices Ha: Density affects firing temperature. Ha: Firing temperature affects density. Ha: Firing temperature does not affect density. Ha: Density does not affect firing temperature.
Compute a one-way ANOVA on the following data using 0.05 significance level. Group A Group B Group C 14 11 14 13 12 12 10 13 13 12 13 12 14 ANOVA Source of Variation SS df MS F P-value F crit Between Groups ? ? ? ? ? Within Groups ? ? ? Total ? ?
Traditional Students (G1) Online Students (G2) mean 2.97 2.95 standard deviation 0.34 0.35 sample size 33 22 significance level: 0.05 degree of freedom: 53 a) what is the t-statistic? Show calculations b) what is the p-value? Show calculations
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