PHOTOSYNTHETIC PIGMENTS1.60.71.4CH30.61.2Soret0.51AHA0.4E0.8COOCH30.30.6 Fphytyl bacteriochlorophyll a0.20.40.10.2300400500600700800700 750 800 850 9002 (nm)2 (nm)Figure 4.7 Absorption (left) and fluorescence (right) spectra of bacteriochlorophyll a in diethyl ether.AbsorbanceCFluorescence (Arbitrary units) 6. Here we have the molecular orbital energy diagram for this chlorophyll molecule. Matchthe absorption peaks labeled in Figure 4.7 above with the transitions shown in themolecular orbital energy diagramLUMO+1LUMOHOMOНОМО-1

Wavelength of absorption is inversely proportional to the energy gap between the two levels.

Here we have the molecular orbital energy diagram for this chlorophyll molecule. Match the absorption peaks labeled in Figure 4.7 above with the transitions shown in the molecular orbital energy diagram LUMO+1 LUMO НОМО НОМО-1

Here we have the molecular orbital energy diagram for this chlorophyll molecule. Match the absorption peaks labeled in Figure 4.7 above with the transitions shown in the molecular orbital energy diagram LUMO+1 LUMO НОМО НОМО-1

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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2. We can form a group of symmetry operations, with our operation being do one operation and do another. For a molecule with an isosceles triangle molecule like water, we talked about the 4 symmetry operations as E (do nothing), C2 (rotation by 180°), σv (the reflection of one hydrogen to the other), and σv’ (the reflection from front to back). By putting coordinates on each of the three atoms (z points along the C2 rotation axis, x points from one hydrogen to the other, and y points out of the plane of the molecule) find the “multiplication” table for this group.
7. Consider the C=O stretching data for the following cyclic ketones: cyclopropane 1813 cm³¹; cyclobutanone 1791 cm³¹; cyclopentanone 1740 cm³¹. (a) which ketone has the strongest bond? (b) where in the trend would you expect the C=O stretch of cyclopropenone? (Use the hybridization information in the same way we used hybridization for C-H stretching.)
1.) Neglecting electron-electron repulsion, write down the ground state of the hydrogen anion H with the electron configuration, 1s?. Include the spatial and spin components. Make sure the wave function (which is the product of space and spin parts) is antisymmetric under the interchange of the two electrons. What is the ground state energy? What is the term symbol for the ground state?
4G I 5:53 2.30 O Yo 40 52% KB/s 1. The C-C stretch in allene (H,C-C=CH,) is about 1650 cm'; the C-H stretch is about 3,100 cm". Calculate the corresponding wavelengths (in nm) and energies (in kJ/mol) of these vibrations. () II
HF, HCN, CCL4 and BR2. Which would have peaks in a pure rotationally spectrum
What IR frequencies would enable a chemist to distinguish between these molecules? CH;CH2OH and CH;CH2OCH;CH3 and CH, HCHCHCCIICH CH, d 3000-3100 cm-1 (=C-H)| 1620-1680 cm-1 (C=C) 3200-3400 cm-1 (OH) || 3000-3100 cm-1 (=C-H)
You are giving a talk at a professional meeting on the absorption spectrum of the HCl molecule (as shown), which has been obtained with a sample including molecules containing only the chlorine-35 atom, so that the double peaks as shown appear as single peaks. After discussing all of the information you can glean about the rotational motion of the molecules from the spectrum, you see a hand raised by a colleague from another university who always asks biting questions. He says, “That’s all well and good, but what about the vibration of the molecule; for example, what is the effective spring constant for the HCl molecule?” You are not upset in the slightest by this question because you prepared in advance for any questions you could think of. You immediately state a numerical value for the effective spring constant of the HCl molecule.
The absorption pattern in the UV/VIS region corresponds to (a) bond vibrations b) valance electron transitions =) molecular rotations E) nuclear spin 0000 a an IR spectrum
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But molecules combine both vibrational and rotational states in such a way that both selection rules must be satisfied if we are only talking about absorption or emission of electromagnetic radiation (i.e. photons). 5 1 images from Krane Ch 9. Relative absorption : 0.330 L=3 to L=2 L=2 to L = 1 Electronic excited state. Electronic ground state L→ L-1 L = 1 to L = 0 Ť 0.340 0.350 SE Energy (eV) 2B 0.360 : hf L=0 L=1 L=2 to to to L = 1 L = 2 L = 3 Photo 4 1 3 1 2 1 1 0 1 1 5 0 4 0 30 20 1 0 0 0 LN L→ L+1 0.370 0.380 no emission here because AL # 0, AL = +1 AN = ±1, HCI spectra. In the middle of the gap is the energy hf that would correspond to a pure vibrational transition, which would violate the rotational selection rule. What is the value of hf for the HCI spectra?
2. Which of the following molecules can produce a microwave rotational spectrum? (Circle all of those that can.) H₂ HBr CH4 CH₂F2 H₂O