6. Given the algebraic expression below: a * d* b-c a) Draw the Expression tree. b) Get the infix, prefix and postfix expression.
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![6. Given the algebraic expression below:
a
* d*
b-c
a)
Draw the Expression tree.
b)
Get the infix, prefix and postfix expression.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd36f2483-fc7f-413a-9376-16fcc6417614%2F154d1da7-b149-4480-9b48-9515a79f91f4%2Fzashfcf_processed.png&w=3840&q=75)
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- 2. Write the following recursive expression tree functions a. Prefix b. Infix c. Postfix d. Evaluate (Evaluate the expression tree-return the value)GIVEN: E -> T – T | T T -> T+F | T*F | T/F | F F -> (E) | Int QUESTION : State the associativity of 4 operators BY DRAWING TREEsB2. b. Given the following infix expression: ((X-Y)/((Z+P) *Q)) 1- Draw the parse tree for this expression 2-Write the equivalent postfix expression
- :what is suffix trie in data structure? How do you show the suffix trie T for eight suffixes of string "maximize" and compact representation of T, for the reference string. 0 1 2 3 4 5 6. 7 i mi a eComputer Science Multiple choice (a) Vending machine is accepting a regular set as input. (b) Vending machine is accepting a context-free set but not a regular set as input. (c) The syntactically correct C++ programs form a context-free set. (d) The syntactically correct C++ programs form a regular set.4. Remove the left recursion from the following production rule to obtain a new rule: A = A '0' | '1' | A '2' | '3' | A '4' | '5'
- 1. Recursion & List processing Write a recursive function flatten that takes a list as an argument and returns the flat version of that list. For example, (flatten '(a (b c) d)) -> (a b c d) (flatten '(((a)) (b (c)) d)-> (a b c d)C++ PROGRAMMINGTopic: Binary Search Trees Explain the c++ code below.: It doesn't have to be long, as long as you explain what the important parts of the code do. (The code is already implemented and correct, only the explanation needed) node* left(node* p) { return p->left; } node* right(node* p) { return p->right; } node* sibling(node* p){ if(p != root){ node* P = p->parent; if(left(P) != NULL && right(P) != NULL){ if(left(P) == p){ return right(P); } return left(P); } } return NULL; } node* addRoot(int e) { if(size != 0){ cout<<"Error"<<endl; return NULL; } root = create_node(e,NULL); size++; return root; } node* addLeft(node* p, int e) { if(p->left == NULL){ node* newLeft =…C++ PROGRAMMINGTopic: Binary Search Trees Explain the c++ code below.: SEE ATTACHED PHOTO FOR THE PROBLEM INSTRUCTIONS It doesn't have to be long, as long as you explain what the important parts of the code do. (The code is already implemented and correct, only the explanation needed) node* left(node* p) { return p->left; } node* right(node* p) { return p->right; } node* sibling(node* p){ if(p != root){ node* P = p->parent; if(left(P) != NULL && right(P) != NULL){ if(left(P) == p){ return right(P); } return left(P); } } return NULL; } node* addRoot(int e) { if(size != 0){ cout<<"Error"<<endl; return NULL; } root = create_node(e,NULL); size++; return root; } node* addLeft(node* p, int e) {…
- Modify the given code to accept float instead of int as a coefficient in C LANGUAGE: // Node structure containing power and coefficient of// variablestruct Node {int coeff;int pow;struct Node* next;}; // Function to create new nodevoid create_node(int x, int y, struct Node** temp){struct Node *r, *z;z = *temp;if (z == NULL) {r = (struct Node*)malloc(sizeof(struct Node));r->coeff = x;r->pow = y;*temp = r;r->next = (struct Node*)malloc(sizeof(struct Node));r = r->next;r->next = NULL;}else {r->coeff = x;r->pow = y;r->next = (struct Node*)malloc(sizeof(struct Node));r = r->next;r->next = NULL;}} // Function Adding two polynomial numbersvoid polyadd(struct Node* poly1, struct Node* poly2,struct Node* poly){while (poly1->next && poly2->next) {// If power of 1st polynomial is greater then 2nd,// then store 1st as it is and move its pointerif (poly1->pow > poly2->pow) {poly->pow = poly1->pow;poly->coeff = poly1->coeff;poly1 =…def optimize_tail_calls(original_scheme_eval): """Return a properly tail recursive version of an eval function.""" def optimized_eval(expr, env, tail=False): """Evaluate Scheme expression EXPR in Frame ENV. If TAIL, return an Unevaluated containing an expression for further evaluation. """ if tail and not scheme_symbolp(expr) and not self_evaluating(expr): return Unevaluated(expr, env) result = Unevaluated(expr, env) # fill in code code here while isinstance(result, Unevaluated): #code here return optimized_eval scheme_eval = optimize_tail_calls(scheme_eval)Explain the various string operations with examples.