6. Given: N₂(g) + 1/2O2(g) = NO(g); K.-7.6x10³ and 2 NO(g) = 2 NO(g) + O₂(g); K=1.1x10What is AG of the following reaction at 25 °C: 2 NO₂(g) = N₂(g) +2 0(g)4(a)-6.4 x 10 J/mol (b)-5.6 x10² J/mol (c)-3.0 x10 J/mol (d) -4.9 x10³ J/mol (e) -6.6 x 10³ J/mol7. Acetic acid (CH₂CO₂H, K, 1.8 Xx105) is the main ingredient in vinegar. A biochemist prepared a 987 mL aqueoussolution by dissolving acetic acid (CH,CO₂H, 0.69 mol) and sodium acetate (CH,CO₂Na, 0.21mol) in pure deionizedwater. What is the pH of this solution?(a) 4.23(b) 5.26(c) -0.52(d) 7.00(e) 0.52

Answered: Image /qna-images/answer/18610aff-b50c-4ba1-bc66-c4776b24c107.jpg

6. Given: N₂(g) + 1/2O2(g) = NO(g); K.-7.6x10³ and 2 NO₂(g) = 2 NO(g) + O₂(g); K=1.1x10 What is AG of the following reaction at 25 °C: 2 NO₂(g) = N₂(g) +2 0(g) (a)-6.4 x 10 J/mol (b)-5.6 x10² J/mol (c)-3.0 x10 J/mol (d) -4.9 x10³ J/mol (e) -6.6 x 10 J/mol

6. Given: N₂(g) + 1/2O2(g) = NO(g); K.-7.6x10³ and 2 NO₂(g) = 2 NO(g) + O₂(g); K=1.1x10 What is AG of the following reaction at 25 °C: 2 NO₂(g) = N₂(g) +2 0(g) (a)-6.4 x 10 J/mol (b)-5.6 x10² J/mol (c)-3.0 x10 J/mol (d) -4.9 x10³ J/mol (e) -6.6 x 10 J/mol

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

6. Given: N₂(g) + 1/2O2(g) = NO(g); K.-7.6x10³ and 2 NO(g) = 2 NO(g) + O₂(g); K=1.1x10
What is AG of the following reaction at 25 °C: 2 NO₂(g) = N₂(g) +2 0(g)
4
(a)-6.4 x 10 J/mol (b)-5.6 x10² J/mol (c)-3.0 x10 J/mol (d) -4.9 x10³ J/mol (e) -6.6 x 10³ J/mol
7. Acetic acid (CH₂CO₂H, K, 1.8 Xx105) is the main ingredient in vinegar. A biochemist prepared a 987 mL aqueous
solution by dissolving acetic acid (CH,CO₂H, 0.69 mol) and sodium acetate (CH,CO₂Na, 0.21mol) in pure deionized
water. What is the pH of this solution?
(a) 4.23
(b) 5.26
(c) -0.52
(d) 7.00
(e) 0.52

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