6. Following is the result of 8 trials of a standard proctor test. Determine the optimum water content and maximum dry unit weight. Determine also the amount of energy expended in the compaction of one of the trials assuming that the test done is standard proctor test. Proctor Mold Volume Mass of wet soil in the Moisture Content Trial (cm³) mold (kG) (%) 1 943.3 1.68 9.9 2 943.3 1.71 10.6 3 943.3 1.77 12.1 4. 943.3 1.83 13.8 5 943.3 1.86 15.1 943.3 1.88 17.4 7 943.3 1.87 19.4 8 943.3 1.85 21.2

6. Following is the result of 8 trials of a standard proctor test. Determine the optimum water content and maximum dry unit weight. Determine also the amount of energy expended in the compaction of one of the trials assuming that the test done is standard proctor test. Proctor Mold Volume Mass of wet soil in the Moisture Content Trial (cm³) mold (kG) (%) 1 943.3 1.68 9.9 2 943.3 1.71 10.6 3 943.3 1.77 12.1 4. 943.3 1.83 13.8 5 943.3 1.86 15.1 943.3 1.88 17.4 7 943.3 1.87 19.4 8 943.3 1.85 21.2

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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1. The results of a standard Proctor test are given in Table Q1 below. Determine the maximum dry density of soil compaction and the optimum moisture content. Table Q1 Volume of Proctor Mass of wet soil in the mold Moisture content mold (cm³) (kg) 3.39 (%) 11.5 987 987 3.87 13.5 987 4.22 15.5 987 5.11 17.5 987 4.75 19.5 987 4.31 21.5
Using Unified Soil Classification System, determine the following: (a) Coefficient of Gradation (b) Group Symbol. Passing No. 4 = 47 % Passing No. 200 = 10 % D10 = 3.45 mm %3! D30 = 6.29 mm De0 = 13.72 mm Plasticity for the minus No. 40 fraction: Liquid Limit = 28 % Plastic Limit = 17 % O GC-GM GP-GC O GC O Coef. Of Gradation = 0.84 O GP O Coef. Of Gradation = 3.97
-1 (a) (b) The results shown in Table QA1 were obtained by a group of students during a laboratory experiment using a standard Proctor test on granular material. Table QA1 Bulk density Water content (Mg/m³) (%) 2 5 6 8 9 1.91 2.24 2.31 1.99 1.4 Using the data in Table QA1, plot the corresponding compaction curve and determine the air content corresponding to the optimum water content and maximum dry density for this soil. Is the air content within the range normally specified when at optimum values? (Note you may Assume: Gs = 2.7 and pw = 1 Mg/m³) Explain why and when it is essential to determine soil density on construction sites.
The following results were obtained from a liquid limit test on a clay using the Casagrande cup device. Number of blows 12 20 28 32 Water content (%) 52.5 47.1 43.2 38.6 37.0 Two determinations for the plastic limit gave water contents of 22.8% and 23.2%. Determine (a) the liquid limit and plastic limit, (b) the plasticity index, (c) the liquidity index if the natural water content is 38% and (d) the void ratio at the liquid limit if G, = 2.7. (e) What is the soil state in the field? (f) Do you expect a brittle type of failure for this soil?
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The results of a Standard Proctor test are given in the following table. Moist Weight of Wet Sol Moisture Content in the mold (Ib) Trial (%) 26 4.08 28 4.12 30 4 4,18 32 Determine: 1. Maximum dry unit weight in Ib/ft^3 (4 decimal places) 2. Optimum water content in % (4 decimal places)
It is needed to determine the moist unit weight of the soil for field compaction testing. A silty soil sample has a mass of 612 grams. The soil sample was then covered in beeswax and the combined weight was 650 g. The soil covered in wax, was then immersed in the water and the graduated cylinder registered a volume difference of 404 ml. The wax was gently peeled off the soil. Moisture content = 12% Specific Gravity = 2.78 But if the wax has a specific gravity of 0.94, determine the following: Dry unit weight of the soil Void ratio of the soil % of air in relation to the soil solids of the sample
6. Following is the result of 8 trials of a standard proctor test. Determine the optimum water content and maximum dry unit weight. Determine also the amount of energy expended in the compaction of one of the trials assuming that the test done is standard proctor test. Proctor Mold Volume Mass of wet soil in the Moisture Content Trial (cm³) mold (kG) (%) 1 943.3 1.68 9.9 943.3 1.71 10.6 3 943.3 1.77 12.1 4 943.3 1,83 13.8 943.3 1.86 15.1 6 943.3 1.88 17.4 943.3 1.87 19.4 8 943.3 1.85 21.2
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Question 11 The results of the particle-size analysis of a soil are as follows: Percent passing the No. 10 sieve = 80 • Percent passing the No. 40 sieve = 40 Percent passing the No. 200 sieve = 20 %3D The liquid limit and plasticity index of the minus No. 40 fraction of the soil are 30 and 5, respectively. Classify the soil by the AASHTO system. A A-2-4 B А-2-6 C) A-3 D A-2-5
A Standard Proctor compaction test was conducted on the soil, with the results shown below. The weight and volume of the mold used in the test were 4.6 lb and 1/30 ft3, respectively, and the mass of the can was 44 grams. Based on the results: Determine the optimum water content and maximum dry unit weight for the borrow soil. Determine the unit weight required for 95% of maximum, and what the range of moisture content for that unit weight is. The sample with the lowest water content was tested for its densest void ratio, which was 0.05, and its loosest void ratio, which was 0.55. Determine its relative density
A sample of soil in its natural state has a volume of 1.396 m3 and weighs 18.662 kN. The sample was taken to the laboratory to determine the mass of solids. After oven-drying, the soil weighs 15.036 kN. If the specific gravity of the soil solids is 2.667, determine the following: Porosity, Degree of saturation, Effective unit weight. show complete solution