6. Find : (a) y = (x +5) tan 7x, %3D dx

Q: 2x-1 dx

A: Given,

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A:

Q: ve

A:

Q: d tanx = sec?x. dx Prove that sec² %3D

A: To prove the equation, we need to simplify the left hand side of the equation. According to the…

Q: Differentiate the function. y = (3x- 1)* (4 - x5) 3 dy dx II

A: To differentiate the given function:

Q: 8. (2x° – 3x) dx

A:

Q: 3. tan x dx

A: Formula: tan2x=sec2x-1

Q: y = In(sec x + tan x)

A: Solve the above differentiation.

Q: find y' for Zy%3D2X-2y

A:

Q: dy y secx + ytanx dx %3D

A: Given differential equation is : dydx=ysecx+ytanx

Q: -dx x +1 2 5.

A:

Q: (1 +Iпx) dx x3

A: The given integral is ∫1+ln xx3dx. Here, u=1+ln x  and  v=1x3.

Q: 4 6 (1+ tan²x) dx =

A:

Q: y = In (tan -1 (8x°)) dy dx II

A:

Q: Find f''(x). f(x) = (x² + 1) ⁹

A: Here we have to find the double derivative of the given two functionsy=(x2+1)9and y=-7x6+1Here these…

Q: Differentiate: y = tan(8x2 – 3x*)

A:

Q: dx ト メ

A: Method of substitution is used