6. Determine the structure of the following compound. Calculate the degrees of unsaturation Identify the relevant peaks in the IR Identify all the peaks in the ¹H NMP. Label each with the identity and a letter so that I can tell which hydrogen you are matching to the molecule. DU-(2-6+2)-(12) = 1 .2 a. b. C. d. C5H12O 1H 1H 100 3 |薄膜法 4500 PPM 2 2000 4H Wolp /cm1 6H 4300 // 0 330
Analyzing Infrared Spectra
The electromagnetic radiation or frequency is classified into radio-waves, micro-waves, infrared, visible, ultraviolet, X-rays and gamma rays. The infrared spectra emission refers to the portion between the visible and the microwave areas of electromagnetic spectrum. This spectral area is usually divided into three parts, near infrared (14,290 – 4000 cm-1), mid infrared (4000 – 400 cm-1), and far infrared (700 – 200 cm-1), respectively. The number set is the number of the wave (cm-1).
IR Spectrum Of Cyclohexanone
It is the analysis of the structure of cyclohexaone using IR data interpretation.
IR Spectrum Of Anisole
Interpretation of anisole using IR spectrum obtained from IR analysis.
IR Spectroscopy
Infrared (IR) or vibrational spectroscopy is a method used for analyzing the particle's vibratory transformations. This is one of the very popular spectroscopic approaches employed by inorganic as well as organic laboratories because it is helpful in evaluating and distinguishing the frameworks of the molecules. The infra-red spectroscopy process or procedure is carried out using a tool called an infrared spectrometer to obtain an infrared spectral (or spectrophotometer).
![**Educational Resource: Compound Structure Determination**
**Task 6: Determine the Structure of the Following Compound**
**a. Calculate the Degrees of Unsaturation (DU):**
The formula for calculating degrees of unsaturation is:
\[ \text{DU} = \frac{(2C + 2 + N - H - X)}{2} \]
Where:
- \( C \) = number of carbons
- \( N \) = number of nitrogens
- \( H \) = number of hydrogens
- \( X \) = number of halogens
For the given compound \( C_5H_{12}O \):
\[ \text{DU} = \frac{(2 \times 5 + 2) - 12}{2} = 1 \]
**b. Identify the Relevant Peaks in the IR:**
The infrared (IR) spectrum shows a broad peak indicating the presence of an O-H group. The peak occurs at around 3300 cm\(^{-1}\), suggesting an alcohol functional group. This observation is marked on the graph with a red "OH" annotation.
**c. Identify All the Peaks in the \( ^1H \) NMR:**
The proton nuclear magnetic resonance (\(^1H\) NMR) spectrum shows several peaks:
- A singlet corresponding to 1 hydrogen (1H)
- A triplet integrating to 4 hydrogens (4H)
- A sextet integrating to 6 hydrogens (6H)
**d. Label Each Peak with the Identity and a Letter:**
- The 1H singlet can be attributed to one type of proton environment.
- The 4H triplet likely corresponds to protons adjacent to a group of CH2 protons.
- The 6H sextet corresponds to protons in another CH2 or CH3 group environment.
**Diagrams:**
1. **IR Spectrum**: Displays a broad O-H stretch around 3300 cm\(^{-1}\), characteristic of alcohols.
2. **\( ^1H \) NMR Spectrum**: Peaks are labelled based on integration, suggesting different hydrogen environments across the compound.
These spectroscopic analyses aid in deducing the structure of the given compound \( C_5H_{12}O \).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F52a5661d-ac5e-4a3e-bd7e-d5daf63e6a76%2F7e76da68-d4b3-459c-b835-4dd13193dfe1%2Fxebt42_processed.jpeg&w=3840&q=75)
Step by step
Solved in 2 steps with 2 images
