**Question 6: Calculation of Specific Rotation**Calculate the specific rotation of a 1.00 g sample dissolved in 20.0 mL of ethanol when 5 mL of this solution are placed in a 200 cm polarimeter tube. The observed rotation is 1.25° counterclockwise.**Explanation:**In this problem, you need to find the specific rotation using the formula:\[ \text{Specific Rotation} = \frac{\text{Observed Rotation} \times 100}{\text{Concentration (g/mL)} \times \text{Path Length (dm)}} \]- **Observed Rotation:** 1.25° counterclockwise (negative since it's counterclockwise)- **Concentration:** To find the concentration, use the total mass of the sample (1.00 g) and the total volume of the solution (20.0 mL).- **Path Length:** 200 cm (which is 20 dm)Substitute the values into the equation to calculate the specific rotation.

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6. Calculate the specific rotation of a 1.00 g sample dissolved in 20.0 mL of ethanol when 5 mL of this solution are placed in a 200 cm polarimeter tube. The observed rotation is 1.25° counterclockwise.

6. Calculate the specific rotation of a 1.00 g sample dissolved in 20.0 mL of ethanol when 5 mL of this solution are placed in a 200 cm polarimeter tube. The observed rotation is 1.25° counterclockwise.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

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