6. Calculate the specific rotation of a 1.00 g sample dissolved in 20.0 mL of ethanol when 5 mL of this solution are placed in a 200 cm polarimeter tube. The observed rotation is 1.25° counterclockwise.

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**Question 6: Calculation of Specific Rotation**

Calculate the specific rotation of a 1.00 g sample dissolved in 20.0 mL of ethanol when 5 mL of this solution are placed in a 200 cm polarimeter tube. The observed rotation is 1.25° counterclockwise.

**Explanation:**

In this problem, you need to find the specific rotation using the formula:

\[ \text{Specific Rotation} = \frac{\text{Observed Rotation} \times 100}{\text{Concentration (g/mL)} \times \text{Path Length (dm)}} \]

- **Observed Rotation:** 1.25° counterclockwise (negative since it's counterclockwise)
- **Concentration:** To find the concentration, use the total mass of the sample (1.00 g) and the total volume of the solution (20.0 mL).
- **Path Length:** 200 cm (which is 20 dm)

Substitute the values into the equation to calculate the specific rotation.
Transcribed Image Text:**Question 6: Calculation of Specific Rotation** Calculate the specific rotation of a 1.00 g sample dissolved in 20.0 mL of ethanol when 5 mL of this solution are placed in a 200 cm polarimeter tube. The observed rotation is 1.25° counterclockwise. **Explanation:** In this problem, you need to find the specific rotation using the formula: \[ \text{Specific Rotation} = \frac{\text{Observed Rotation} \times 100}{\text{Concentration (g/mL)} \times \text{Path Length (dm)}} \] - **Observed Rotation:** 1.25° counterclockwise (negative since it's counterclockwise) - **Concentration:** To find the concentration, use the total mass of the sample (1.00 g) and the total volume of the solution (20.0 mL). - **Path Length:** 200 cm (which is 20 dm) Substitute the values into the equation to calculate the specific rotation.
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