6. A student titrated 30.00 mL of a hydrochloric acid solution with 1.00 M sodium hydroxide. The sodium hydroxide was initially filled to the 2.30 mL mark on the burette. Once the level in the burette reached 50.00 mL, the student was forced to refill the burette and did so to the 5.06 mL mark. The endpoint was finally reached when the sodium hydroxide level dropped to 32.09 mL on the burette. What is the molarity of the acid solution? Show work. 7. How many milliliters of a 0.250 M sulfuric acid solution would be required to completely react with 2.398 grams of solid aluminum hydroxide? Work must be shown.
6. A student titrated 30.00 mL of a hydrochloric acid solution with 1.00 M sodium hydroxide. The sodium hydroxide was initially filled to the 2.30 mL mark on the burette. Once the level in the burette reached 50.00 mL, the student was forced to refill the burette and did so to the 5.06 mL mark. The endpoint was finally reached when the sodium hydroxide level dropped to 32.09 mL on the burette. What is the molarity of the acid solution? Show work. 7. How many milliliters of a 0.250 M sulfuric acid solution would be required to completely react with 2.398 grams of solid aluminum hydroxide? Work must be shown.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Transcribed Image Text:6. A student titrated 30.00 mL of a hydrochloric acid solution with 1.00 M sodium hydroxide. The
sodium hydroxide was initially filled to the 2.30 mL mark on the burette. Once the level in the burette
reached 50.00 mL, the student wasforced to refill the burette and did so to the 5.06 mL mark. The
endpoint was finally reached when the sodium hydroxide level dropped to 32.09 mL on the
burette. What is the molarity of the acid solution? Show work.
7. How many milliliters of a 0.250 M sulfuric acid solution would be required to completely react with
2.398 grams of solid aluminum hydroxide? Work must be shown.
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