6. A spherically shaped balloon has a radius of 13.5 m, and is filled with helium. How much extra mass can a cargo lift, assuming that the skin and the cargo of the balloon have a mass of 900 kg? Neglect the buoyant force on the cargo volume itself. (The density of air is 1.29 kg/m3 and the density of helium is 0.179 kg/m³)

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**Problem 6: Buoyancy and Lifting Capacity of a Spherical Helium Balloon**

A spherically shaped balloon has a radius of 13.5 meters and is filled with helium. Determine the additional mass a cargo can lift, provided that the combined mass of the balloon's skin and cargo is 900 kilograms. For this calculation, neglect the buoyant force acting on the cargo's volume itself. 

- The density of air is given as 1.29 kg/m³.
- The density of helium is 0.179 kg/m³.

**Solution:**

To find the extra mass that can be lifted, calculate the buoyant force and subtract the mass of the helium and balloon structure. Let's assume that `V` is the volume of the balloon, `ρ_air` is the density of air, and `ρ_helium` is the density of helium. 

1. Calculate the volume of the balloon using the formula for the volume of a sphere:
   \[
   V = \frac{4}{3} \pi r^3
   \]
   where \( r = 13.5 \) meters.

2. Use the volume to determine the buoyant force:
   \[
   \text{Buoyant Force} = V \times \rho_{\text{air}} \times g
   \]
   where \( g \approx 9.81 \, \text{m/s}^2 \).

3. Calculate the weight of the helium in the balloon:
   \[
   \text{Weight of Helium} = V \times \rho_{\text{helium}} \times g
   \]

4. Determine the lifting capacity by subtracting the mass of the balloon and helium from the buoyant force and include the initial mass:
   \[
   \text{Extra Mass Lifted} = \left(\frac{\text{Buoyant Force} - \text{Weight of Helium}}{g}\right) - \text{Mass of Balloon+Cargo}
   \] 

Round off your answer to the nearest kilogram.
Transcribed Image Text:**Problem 6: Buoyancy and Lifting Capacity of a Spherical Helium Balloon** A spherically shaped balloon has a radius of 13.5 meters and is filled with helium. Determine the additional mass a cargo can lift, provided that the combined mass of the balloon's skin and cargo is 900 kilograms. For this calculation, neglect the buoyant force acting on the cargo's volume itself. - The density of air is given as 1.29 kg/m³. - The density of helium is 0.179 kg/m³. **Solution:** To find the extra mass that can be lifted, calculate the buoyant force and subtract the mass of the helium and balloon structure. Let's assume that `V` is the volume of the balloon, `ρ_air` is the density of air, and `ρ_helium` is the density of helium. 1. Calculate the volume of the balloon using the formula for the volume of a sphere: \[ V = \frac{4}{3} \pi r^3 \] where \( r = 13.5 \) meters. 2. Use the volume to determine the buoyant force: \[ \text{Buoyant Force} = V \times \rho_{\text{air}} \times g \] where \( g \approx 9.81 \, \text{m/s}^2 \). 3. Calculate the weight of the helium in the balloon: \[ \text{Weight of Helium} = V \times \rho_{\text{helium}} \times g \] 4. Determine the lifting capacity by subtracting the mass of the balloon and helium from the buoyant force and include the initial mass: \[ \text{Extra Mass Lifted} = \left(\frac{\text{Buoyant Force} - \text{Weight of Helium}}{g}\right) - \text{Mass of Balloon+Cargo} \] Round off your answer to the nearest kilogram.
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