A naval mine is a sphere (V=4/3 ttr^3 ) of radius 0.5 m that would normally float in water (p_water=1000 kg/m^3 ) . The mine (p_mine=700 kg/m^3 ) is held under the surface by a cable that attaches it to the sea floor. a. Find the volume of the naval mine. b. Find the mass of the naval mine. c. Find the tension in the cable that holds the mine under the surface using Newton's Second Law.
A naval mine is a sphere (V=4/3 ttr^3 ) of radius 0.5 m that would normally float in water (p_water=1000 kg/m^3 ) . The mine (p_mine=700 kg/m^3 ) is held under the surface by a cable that attaches it to the sea floor. a. Find the volume of the naval mine. b. Find the mass of the naval mine. c. Find the tension in the cable that holds the mine under the surface using Newton's Second Law.
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Transcribed Image Text:A naval mine is a sphere (V = 4/3 πr^3) of radius 0.5 m that would normally float in water (ρ_water = 1000 kg/m^3). The mine (ρ_mine = 700 kg/m^3) is held under the surface by a cable that attaches it to the sea floor.
a. Find the volume of the naval mine.
b. Find the mass of the naval mine.
c. Find the tension in the cable that holds the mine under the surface using Newton's Second Law.
Expert Solution

Step 1
Given,
Radius of the naval mine = 0.5m
Density of water = 1000 kg/m3
Density of naval mine = 700 kg/m3
Based on this, we have to answer part (a), (b) and (c). Let's see how we do it :
Step by step
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