6. A four-stroke, 6-cylinder, 3.6 Itr SI engine, is designed to have a maximum speed of 6000 rn m At this speed, the volumetric efficiency of the engine is 0.92, fuel density is 700 kg/m. C = %3D 0 85. Ce= 0.6. Ap. = 0.07 bar, at sea level 1a-27-C, Pa= 1.03 bar, and AF 15. Calculate: (1) Throat diameter of the carburetor. (2) Fuel orifice area. (3) AF at altitude of 4000
6. A four-stroke, 6-cylinder, 3.6 Itr SI engine, is designed to have a maximum speed of 6000 rn m At this speed, the volumetric efficiency of the engine is 0.92, fuel density is 700 kg/m. C = %3D 0 85. Ce= 0.6. Ap. = 0.07 bar, at sea level 1a-27-C, Pa= 1.03 bar, and AF 15. Calculate: (1) Throat diameter of the carburetor. (2) Fuel orifice area. (3) AF at altitude of 4000
Elements Of Electromagnetics
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ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
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
Transcribed Image Text:6. A four-stroke, 6-cylinder, 3.6 Itr SI engine, is designed to have a maximum speed of 6000 r.p.m.
At this speed, the volumetric efficiency of the engine is 0.92, fuel density is 700 kg/m C
15. Calculate: (1)
%3!
0.85, C 0.6, Apg = 0.07 bar, at sea level T, = 27°C, p. = 1.03 bar, and AE
Throat diameter of the carburetor. (2) Fuel orifice area. (3) AF at altitude of 4000 m
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