6. A cigarette manufacturer has designed a new filter for the filtered cigarettes it produces. The following hypotheses are beingtested:Ho: the new filter is effective in reducing tarH₁: the new filter is not effective in reducing tarWould concluding that the new filter is effective in reducing tar when it actually is not effecuve be an example of a Type 1 or Type 2error?Would this be a serious error to make? Explain.

Concluding that the new filter is effective in reducing tar when it actually is not would be an…

Answered: 6. A cigarette manufacturer has…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Dr. Mackintosh believes a new olfactory therapy would be more successful in promoting weight loss among obese patients. His patients are first weighed and then randomly assigned to olfactory therapy, dance therapy, or a control condition. At the end of the three weeks, the amount of weight lost is recorded. The results indicate no significant difference in the amount of weight lost between the three conditions. If true differences existed between the conditions, but they were not detected, what kind of error occurred?
Identify the type I error and the type II error that corresponds to the given hypothesis. The proportion of adults who use the internet is greater than 0.27. Which of the following is a type I error? O A. Reject the claim that the proportion of adults who use the internet is 0.27 when the proportion is actually 0.27. O B. Fail to reject the claim that the proportion of adults who use the internet is 0.27 when the proportion is actually different from 0.27. O C. Reject the claim that the proportion of adults who use the internet is 0.27 when the proportion is actually different from 0.27. O D. Fail to reject the claim that the proportion of adults who use the internet is 0.27 when the proportion is actually 0.27. Which of the following is a type II error? O A. Fail to reject the claim that the proportion of adults who use the internet is 0.27 when the proportion is actually 0.27. O B. Reject the claim that the proportion of adults who use the internet is 0.27 when the proportion is…
A researcher is interested in the effect of the pandemic on social media use among college students. The researcher hypothesizes that college students spend more time on social media thanthey did before the pandemic. To test his hypothesis, he randomly selected 50 college students and asked how many hours do they spend on social media per day before and after the pandemic. a) What is the research question? b) What is/are the variable(s)? What graphs can be used to display the variable(s) visually? c) What statistical test can be used to answer the research question?
A local coach wants to see if training in light rooms or dark rooms impacts athlete performance. With the single team, the coach tries training in different conditions and takes measurements. She ran her analysis in Microsoft Excel and received the following output table. If the P value is less than 0.05, the null hypothesis may be rejected. Based on the data table, what decision should the coach make about the hypothesis? Coach should reject the null hypothesis. Coach should fail to reject the null hypothesis. Coach should accept the null hypothesis. Coach does not have enough information to decide.
1. For each row of the table you are given a p-value and a level of significance (a). Determine which hypothesis is supported, if the data are significant and which type error could be made. If a given p- value is not a valid p-value (because it is greater than 1), put an x in each box in therow. p-value Hypothesis Họ or H1 Significant or Not Significant Error Type I or Type II 0.043 0.05 0.32 0.05 0.043 0.01 0.0035 0.01 0.043 0.10 0.15 0.10 5.6 x 106 0.05 7.3256 0.01 2. For the hypothesis test, write the concluding sentence in the form used by researchers. Context: Support paying off student dept, H1: p 8 ft, p-value-5.6 x 10°, a=0.05, n=56. 4. For the hypothesis test, write the concluding sentence in the form used by researchers. Context: Blood pressure for men and women, H1: Hw # HM ft, p-value3D0.0035, a=0.01, n=2403.
I am testing whether a new group study technique improves PSYC 214 students’ final exam grades. In this situation, what would be a Type I error? What would be a Type II error?
Three students, an athlete, a fraternity member, and an honors student, record the number of hours they slept each night for 20 nights. O JMP Applet imp ? Oneway Analysis of Sleep Hours By Student Oneway Analysis of Sleep Hours By Student 10 Oneway Anova 14 Summary of Fit 12 Rsquare 0.024506 10- Adj Rsquare Root Mean Square Error Mean of Response Observations (or Sum Wgts) -0.00072 1.99517 7.7 60 Analysis of Variance Sum of Mean F Prob > Source DF Squares Square Ratio F 2 Athiete Frat Honors Student 2 5.70000 2.85000 0.7180 0.4931 Student Error 57 226.90000 3.98070 C. Total 59 232.60000 Oneway Anova Means for Oneway Anova Std Lower Upper 95% Summary of Fit Level Number Mean Error 95% Athlete 20 8.10000 0.44813 7.2086 8.9934 Rsquare 0.024506 Frat 20 7.65000 0.44813 6.7588 8.5434 Adj Rsquare Root Mean Square Error Mean of Response Observations (or Sum Wgts) -0.00972 Honors 20 7.35000 0.44813 6.4586 8.2434 1.99517 Std Error uses a pooled estimate of error variance 7.7 60 Analysis of…
A demographer wants to know what proportion of women in different countries dye their hair. They take a random sample of women from Korea and another random sample of women from China. In Korea, 47% dyed their hair. In China, 56% dyed their hair. (a) What hypotheses would the demographer use to test if women in China are more likely to dye their hair than women in Korea? H0: pChina=pKorea vs. Ha: pChina ≠ pKoreaH0: pChina - pKorea = 0 vs. Ha: pChina - pKorea > 0 H0: μChina-μKorea = 0 vs. Ha: μChina-μKorea ≠ 0H0: pChina-pKorea = 0.09 vs. Ha: pChina-pKorea ≠ 0.09H0: μChina = 0.56 vs. Ha: μKorea = 0.47 (b) Suppose their test yielded a p-value of 0.079. What does this mean in the context of the test? We are 7.9% confident that the results of our test are correct.If the women of two countries have the same rates of coloring their hair, the probability of getting a difference at least this large is 0.079. If we take another sample, the probability of getting the same p̂China and…

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