Part a and part b. Show all work. Include sketch with labels 6. A 6.1 ft tall shopper in a department store is 15 ft from a convex security mirror.The shopper notices that his image in the mirror appears to be only 6.9 in tall. (a)Is the shopper's image upright or inverted? Explain. (b) What is the mirror'sradius of curvature?Draw the Ray diagram of the object and its image.Please draw all three rays that show where the image is located.

Solution : - Given : Height of the shopper h_0 = 6.1 ft Distance from mirror u = -15 ft Height of the image = 6.9 inch = 0.575 ft Using formula of magnification m = h_x/h_0 = - v/u 0.575/6.1 = (-v/(-1.5)) v = 1.413 ft Here v is the distance of image from mirror which is 1.413 ft right from mirror since m = h_I/h_0 = - (v/u) = - (1.413/(-15)) = 0.0942 is +ve hence shoppers image is upright. (b) Using mirror formula (1/v ) + (1/u) = 1/f or 1/v + 1/u = 2/R R = -42.39/(-13.587) = 3.11 ft Hence radius of curvature is 3.11 ft.

Answered: 6. A 6.1 ft tall shopper in a…

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Part a and part b. Show all work. Include sketch with labels

6. A 6.1 ft tall shopper in a department store is 15 ft from a convex security mirror.
The shopper notices that his image in the mirror appears to be only 6.9 in tall. (a)
Is the shopper's image upright or inverted? Explain. (b) What is the mirror's
radius of curvature?
Draw the Ray diagram of the object and its image.
Please draw all three rays that show where the image is located.

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(c) Where would the shoplifter’s distance from the
mirror be if his image were located at the focal point of the convex mirror.

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