6. +-2 points SerCP11 19.3.P.006.MI. My Notes Ask Your Teach A proton moves perpendicular to a uniform magnetic field B at a speed of 1.10 x 107 m/s and experiences an acceleration of 3.00 x 1013 m/s2 in the positive x-direction when its velocity is in the positive z-direction. Determine the magnitude and direction of the field magnitude direction | Select…수! Need Help? Read ItMaster ft

6. +-2 points SerCP11 19.3.P.006.MI. My Notes Ask Your Teach A proton moves perpendicular to a uniform magnetic field B at a speed of 1.10 x 107 m/s and experiences an acceleration of 3.00 x 1013 m/s2 in the positive x-direction when its velocity is in the positive z-direction. Determine the magnitude and direction of the field magnitude direction | Select…수! Need Help? Read ItMaster ft

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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< Inbox 111 Primary Hitham Wahed. An electron moves along the z-axis with Vz v₂ = 2.6 x 107 m/s. As it passes the origin, what are the strength and direction of the magnetic field at the following (x, y, z) positions? Promotions 50 new Quizlet, QuillBot, Adobe Creativ... Sent from iPhone ▼ Part A Social 23 new Facebook (1.0 cm, 0 cm, 0 cm) Express your answers in teslas separated by commas. ▸View Available Hint(s) B₂, By, B₂ = 195 ΑΣΦ ? T Try a fast, secure browser with updates built in
6. Refer to the diagram For the moment please disregard the moving charge off to the right. The diagram above shows segments of two long straight wires, carrying currents I_1 = 3.97 A and I_2 = 2.88 A respectively. The distance between the wires is 1.99 cm. What is the force on a 5.57-cm segment of wire #2 due to the magnetic field from wire #1? 5.12E-06 N 7.68E-06 N 1.09E-05 N 6.40E-06 N
001 (part 1 of 2) A uniform 3.9 T magnetic field points north. If an electron moves vertically downward (to- ward the ground) with a speed of 2.8 x 10 m/s through this field. The charge on a proton is 1.60x10 a) What is the magnitude of the force acting -19 on it? Answer in units of N. b) What is the direction of the force? 1. North 2. None of these 3. South 4. West 5. East
What is the magnitude force on a proton moving at 2.5 × 105 m/s in a magnetic field 0.5T If the velocity id parallel to magnetic field? A. 0 ●●● B. 2.0 x 10-14 N C. 1.0 X 10-14 N D. 4.0 x 10-14 N A B B D CA D с
1. In the diagram below, a charged particle enters a region of uniform magnètic field where B 0.6 T. The particle has an initial speed of 2.7 x 106 m/s. Keep in mind Newton's Second Law and recall the equation for centripetal acceleration: 1²/r. a. Ignore gravity and first determine the sign of the charged particle if it follows the trajectory of the dashed semicircle. b. Next, use the information given to derive an equation for the charge-to-mass ratio (q/m) of the particle in terms of the particle's speed, the magnitude of the magnetic field and the radius of the semicircle. c. Lastly, calculate the charge to mass ratio of this particle. 95.0 cm B
Can you answer problem 5? Can you also provide a short explanation for the answer you chose?