6) Use the definition of the Laplace transform, F(t) = | f(t) e*"dt , to find L{sin kt} . Compare how the calculation of the Laplace transform of sin 2t was shown in the book. -e-s sin 2t L{sin 2r) e sin 2r dt = e-s cos 2t dt %3D es cos 2t dt, s >0. %3D lim e cos 2r 0, s >0 Laplace transform of sin 21 -e-st cos 2t es sin 21 dt 4. L{sin 2r). %3D At this point we have an equaion with L{sin 21) on both sides of the equality. Solving for that quantity yields the result 2 L sin 21) =- s>0, +4 DO NOT copy this solution with 2 replaced by k. It leaves out too many steps. Your job is to make the calculation of L{sin kt} understandable. Show the steps as done in class including the integration by parts by the tabular method and the calculation of the improper integrals. I.

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter6: The Trigonometric Functions
Section6.6: Additional Trigonometric Graphs
Problem 77E
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6) Use the definition of the Laplace transform, F(t) = f)e"dt, to find L{sin kt} .
Compare how the calculation of the Laplace transform of sin 2t was shown in the book.
-e-st sin 2t
L{sin 2r)
e sin 2r dt =
est cos 2t dt
%3D
一
e cos 2t dt,
s >0.
%3D
lim e
cos 2r 0, s >0
Laplace transform of sin 2r
-est cos 2t
est sin 2r dt
4.
L{sin 2r}.
At this point we have an equaion with L{sin 21) on both sides of the equality.
Solving for that quantity yields the result
2
L sin 2) =
s>0,
DO NOT copy this solution with 2 replaced by k. It leaves out too many steps.
Your job is to make the calculation of L{sin kt} understandable.
Show the steps as done in class including the integration by parts by the tabular method and
the calculation of the improper integrals.
I.
Transcribed Image Text:6) Use the definition of the Laplace transform, F(t) = f)e"dt, to find L{sin kt} . Compare how the calculation of the Laplace transform of sin 2t was shown in the book. -e-st sin 2t L{sin 2r) e sin 2r dt = est cos 2t dt %3D 一 e cos 2t dt, s >0. %3D lim e cos 2r 0, s >0 Laplace transform of sin 2r -est cos 2t est sin 2r dt 4. L{sin 2r}. At this point we have an equaion with L{sin 21) on both sides of the equality. Solving for that quantity yields the result 2 L sin 2) = s>0, DO NOT copy this solution with 2 replaced by k. It leaves out too many steps. Your job is to make the calculation of L{sin kt} understandable. Show the steps as done in class including the integration by parts by the tabular method and the calculation of the improper integrals. I.
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