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(6) For the above problem obtain the conditional density fy[x=x(V). The following answers are proposed. (a) For x E (–1, 1), the conditional density of Y given X = x is S* if 0 < y < x², fyjx=x (v) = otherwise. (b) For y € (0, x²), the conditional density of Y given X = x is if – 1 < x < 1, fyjx=x (y) = otherwise. (C) For y € (0, x²), the conditional density of Y given X = x is 3y2 S* if - 1 < x < 1, fyjx=x (y) = otherwise. (d) For x E (-1, 1), the conditional density of Y given X = x is 3y2 fyjx=x(v) = * if 0 < y < x?, otherwise.

(6) For the above problem obtain the conditional density fy[x=x(V). The following answers are proposed. (a) For x E (–1, 1), the conditional density of Y given X = x is S* if 0 < y < x², fyjx=x (v) = otherwise. (b) For y € (0, x²), the conditional density of Y given X = x is if – 1 < x < 1, fyjx=x (y) = otherwise. (C) For y € (0, x²), the conditional density of Y given X = x is 3y2 S* if - 1 < x < 1, fyjx=x (y) = otherwise. (d) For x E (-1, 1), the conditional density of Y given X = x is 3y2 fyjx=x(v) = * if 0 < y < x?, otherwise.

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
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Please just answer problem 6. In problem 6, it says "from the above problem", the above problem is problem 5 which is also attached. So nothing is missing here. Thank you for your great effort. 

(6) For the above problem obtain the conditional density fy|X=x (y). The following answers are proposed. (a) For x E (-1, 1), the conditional density of Y given X = x is 3x2 if 0 < y < x², fyx=x (y) = otherwise. (b) For y E (0,x²), the conditional density of Y given X = x is 3x2 if – 1 < x < 1, fy|x=x (y) : otherwise. (c) For y E (0, x²), the conditional density of Y given X = x is 3y2 if – 1 < x < 1, fy|x=x (y): x6 otherwise. (d) For x E (-1, 1), the conditional density of Y given X = x is 3y2 if 0 < y < x², frjx=x (V) = x6 otherwise. (e) None of the above The correct answer is (a) (b) (c) (d) (e) N/A (Select One)
Transcribed Image Text:(6) For the above problem obtain the conditional density fy|X=x (y). The following answers are proposed. (a) For x E (-1, 1), the conditional density of Y given X = x is 3x2 if 0 < y < x², fyx=x (y) = otherwise. (b) For y E (0,x²), the conditional density of Y given X = x is 3x2 if – 1 < x < 1, fy|x=x (y) : otherwise. (c) For y E (0, x²), the conditional density of Y given X = x is 3y2 if – 1 < x < 1, fy|x=x (y): x6 otherwise. (d) For x E (-1, 1), the conditional density of Y given X = x is 3y2 if 0 < y < x², frjx=x (V) = x6 otherwise. (e) None of the above The correct answer is (a) (b) (c) (d) (e) N/A (Select One)
(5) A bivariate density is -{** Sx² y², if x € (-1, 1), 0 < y < x² f(x, у) :%3D otherwise. The marginal densities of X and Y are fx(x) = **, xE (-1, 1); fr(v) = 9y²(1 – y³2), 0 < y < 1. Obtain the conditional density fx|Y=y(x). The following answers are proposed. (a) For y E (0, 1), the conditional density of X given Y = y is 3x2 if y < x² < 1, fx\Y=y (x) = 2(1-y3/2) otherwise. (b) For y E (x², 1), the conditional density of X given Y = y is 3x2 if 0 < y < 1, fx\Y=y (x) = 2(1-y3/2) otherwise. (c) For y E (x², 1), the conditional density of X given Y = y is Зу? {; if 0 < y < 1, fx\Y=y (x) = 2(1+y3/2) otherwise. (d) For y E (0, 1), the conditional density of X given Y = y is 3y? 2(1+y3/2) if y < x? < 1, fx\Y=y (x) = otherwise. (e) None of the above The correct answer is (a) (b) (c) (d) (e) N/A (Select One)
Transcribed Image Text:(5) A bivariate density is -{** Sx² y², if x € (-1, 1), 0 < y < x² f(x, у) :%3D otherwise. The marginal densities of X and Y are fx(x) = **, xE (-1, 1); fr(v) = 9y²(1 – y³2), 0 < y < 1. Obtain the conditional density fx|Y=y(x). The following answers are proposed. (a) For y E (0, 1), the conditional density of X given Y = y is 3x2 if y < x² < 1, fx\Y=y (x) = 2(1-y3/2) otherwise. (b) For y E (x², 1), the conditional density of X given Y = y is 3x2 if 0 < y < 1, fx\Y=y (x) = 2(1-y3/2) otherwise. (c) For y E (x², 1), the conditional density of X given Y = y is Зу? {; if 0 < y < 1, fx\Y=y (x) = 2(1+y3/2) otherwise. (d) For y E (0, 1), the conditional density of X given Y = y is 3y? 2(1+y3/2) if y < x? < 1, fx\Y=y (x) = otherwise. (e) None of the above The correct answer is (a) (b) (c) (d) (e) N/A (Select One)
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