6-20 In Fig. 6-30, solve for R, h, V, V,, V Vụ l, b, , and .Figure 6-30R = 75 0R= 150 NV = 12 VR23D330 ΩR4 = 180 2Figure 6-44AUnknown resistorR.V = 10 VLAODRatio armStandard resistorVariable from099,999 nin 1-0 steps6-35 In Fig. 6-44, assume that the bridge is balanced whenR, = 1 kN, R, = 5 kN, and R, = 34,080N. Determinea. the value of the unknown resistor, R,.b. the voltages Ven and Vog-c. the total current, 4, flowing to and from the voltagesource, V.

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Answered: 6-20 In Fig. 6-30, solve for R, h, V,…

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Electrical Engineering

6-20 In Fig. 6-30, solve for R, h, V, V, V Vụ , b, , and . Figure 6-30 R = 750 R= 150 N V = 12 V R= 330 N R= 180 2

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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Concept explainers

Current Division Method

The generalized current divider formula is given by the following relation below,

Question

6-20 In Fig. 6-30, solve for R, h, V, V,, V Vụ l, b, , and .
Figure 6-30
R = 75 0
R= 150 N
V = 12 V
R23D330 Ω
R4 = 180 2
Figure 6-44
A
Unknown resistor
R.
V = 10 V
LA
OD
Ratio arm
Standard resistor
Variable from
099,999 n
in 1-0 steps
6-35 In Fig. 6-44, assume that the bridge is balanced when
R, = 1 kN, R, = 5 kN, and R, = 34,080N. Determine
a. the value of the unknown resistor, R,.
b. the voltages Ven and Vog-
c. the total current, 4, flowing to and from the voltage
source, V.

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