6 0 Let A = |0 3 Lo 3 3] (a) Find the characteristic polynomial of A. (b) Find the eigenvalues of A and their corresponding eigenspaces. (c) Is A diagonalizable? Explain.

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### Matrix Analysis

Given the matrix \( A \):

\[ A = \begin{bmatrix} 6 & 0 & 0 \\ 0 & 3 & 3 \\ 0 & 3 & 3 \end{bmatrix} \]

We are required to perform the following tasks:

#### (a) Find the characteristic polynomial of \( A \).

The characteristic polynomial of a matrix \( A \) is given by the determinant:

\[ \text{det}(A - \lambda I) \]

where \( \lambda \) is a scalar and \( I \) is the identity matrix. For the matrix given, we have:

\[ A - \lambda I = \begin{bmatrix} 6 - \lambda & 0 & 0 \\ 0 & 3 - \lambda & 3 \\ 0 & 3 & 3 - \lambda \end{bmatrix} \]

#### (b) Find the eigenvalues of \( A \) and their corresponding eigenspaces.

To find the eigenvalues, solve the characteristic equation obtained in part (a). The roots of this polynomial are the eigenvalues of \( A \). Once the eigenvalues are found, the eigenspaces can be determined by solving:

\[ (A - \lambda I) \mathbf{x} = 0 \]

for each eigenvalue \( \lambda \).

#### (c) Is \( A \) diagonalizable? Explain.

A matrix \( A \) is diagonalizable if there exists a matrix \( P \) such that \( P^{-1}AP \) is a diagonal matrix. This typically occurs if \( A \) has \( n \) linearly independent eigenvectors, where \( n \) is the size of the matrix.

1. **Characteristic Polynomial:**
    \[
    \text{det}(A - \lambda I) = \text{det}\left( \begin{bmatrix}
    6 - \lambda & 0 & 0 \\
    0 & 3 - \lambda & 3 \\
    0 & 3 & 3 - \lambda
    \end{bmatrix} \right)
    \]

2. **Eigenvalues:**
    Solve the characteristic polynomial to find the eigenvalues. Then, determine the eigenspaces for each eigenvalue \( \lambda \).

3. **Diagonalizability:**
    Check if the number of linearly
Transcribed Image Text:### Matrix Analysis Given the matrix \( A \): \[ A = \begin{bmatrix} 6 & 0 & 0 \\ 0 & 3 & 3 \\ 0 & 3 & 3 \end{bmatrix} \] We are required to perform the following tasks: #### (a) Find the characteristic polynomial of \( A \). The characteristic polynomial of a matrix \( A \) is given by the determinant: \[ \text{det}(A - \lambda I) \] where \( \lambda \) is a scalar and \( I \) is the identity matrix. For the matrix given, we have: \[ A - \lambda I = \begin{bmatrix} 6 - \lambda & 0 & 0 \\ 0 & 3 - \lambda & 3 \\ 0 & 3 & 3 - \lambda \end{bmatrix} \] #### (b) Find the eigenvalues of \( A \) and their corresponding eigenspaces. To find the eigenvalues, solve the characteristic equation obtained in part (a). The roots of this polynomial are the eigenvalues of \( A \). Once the eigenvalues are found, the eigenspaces can be determined by solving: \[ (A - \lambda I) \mathbf{x} = 0 \] for each eigenvalue \( \lambda \). #### (c) Is \( A \) diagonalizable? Explain. A matrix \( A \) is diagonalizable if there exists a matrix \( P \) such that \( P^{-1}AP \) is a diagonal matrix. This typically occurs if \( A \) has \( n \) linearly independent eigenvectors, where \( n \) is the size of the matrix. 1. **Characteristic Polynomial:** \[ \text{det}(A - \lambda I) = \text{det}\left( \begin{bmatrix} 6 - \lambda & 0 & 0 \\ 0 & 3 - \lambda & 3 \\ 0 & 3 & 3 - \lambda \end{bmatrix} \right) \] 2. **Eigenvalues:** Solve the characteristic polynomial to find the eigenvalues. Then, determine the eigenspaces for each eigenvalue \( \lambda \). 3. **Diagonalizability:** Check if the number of linearly
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