-5t x" +6x' +5x = 30 e ", x(0) = 8, x'(0) = 28 Solve the IVP and find x(0.25) to at least four decimal places of accuracy. Put x(0.25) in the answer box.
-5t x" +6x' +5x = 30 e ", x(0) = 8, x'(0) = 28 Solve the IVP and find x(0.25) to at least four decimal places of accuracy. Put x(0.25) in the answer box.
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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6) Solve the following problem, provide a well explained, correct and readable solution.
![### Differential Equation Problem
Given the initial value problem (IVP):
\[ x'' + 6x' + 5x = 30 e^{-5t}, \]
with initial conditions
\[ x(0) = 8, \quad x'(0) = 28. \]
Solve the IVP and find \( x(0.25) \) to at least four decimal places of accuracy. Enter your answer in the answer box.
---
### Explanation
This problem involves solving a second-order linear differential equation with constant coefficients. The equation has a non-homogeneous part, \( 30 e^{-5t} \), which requires determining the particular solution. Initial conditions are provided to find the specific solution. The task demands accuracy to four decimal places for the value at \( t = 0.25 \).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F17facbba-2b30-49af-b629-17c601c4bf12%2F54815208-d14c-4df4-bf39-cafdeec801e9%2F8kiwr4p_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Differential Equation Problem
Given the initial value problem (IVP):
\[ x'' + 6x' + 5x = 30 e^{-5t}, \]
with initial conditions
\[ x(0) = 8, \quad x'(0) = 28. \]
Solve the IVP and find \( x(0.25) \) to at least four decimal places of accuracy. Enter your answer in the answer box.
---
### Explanation
This problem involves solving a second-order linear differential equation with constant coefficients. The equation has a non-homogeneous part, \( 30 e^{-5t} \), which requires determining the particular solution. Initial conditions are provided to find the specific solution. The task demands accuracy to four decimal places for the value at \( t = 0.25 \).
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