Answered: 5kN AD 3m

Engineering

Civil Engineering

5kN AD 3m

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Related questions

Q: 15 kN/m 5 kN/m 9 m

A: Given data Simply supported beam UVL Span length I will break the given loading into UDL and UVL

Q: support B? a. 68.145 kN-m b. -68.145 kN-m c. 28.43 kN-m d. -28.43 kN-m What is the final moment at…

A: A indeterminate beam is given with loading as mentioned. To determine The final moment at A The…

Q: SITUATION 5. For Items 12-14. 12. Find the force acting on member FE. a. 1.803 kN "T" 1.Şm H b.…

Q: rent Attempt ln Progress Determine the shear force Vin the beam at a point located 0.70 m to the…

A: Given data, By = 300 kN Cy = 125 kN

Q: 1.533 KN 1.202 KN 3.066 kN B 2.403 KN 3.086 KN 2.403 kN 3.000 KN G 3.000 KN IMH 2.403 kN 2.403 KN…

Q: Determine the shear force V in the beam at the point located 0.75 m to the right of point B. The…

Q: Situation 4: A truck with axle loads of 40 kN and 60 kN on a wheel base of 5 m rolls across a 10 m…

Q: Problem 3) Determine the maximum positive moment at point C on the single girder caused by the…

A: Determine the maximum positive moment at point C on the single girder caused by the moving load.

Q: 8-56. Solve Prob. 8-55 using Castigliano's theorem. A 6 kN/m -2 m- B C Probs. 8-55/56 3 m 12 kN

A: first find strain energy. after that apply castigliano's theorem to find deflection in vertical…

Q: Three wheel loads rolls as aunilacrossa 12 spt The loads areA 15 kN; B-25 kN. 2 m to the right of A…

Q: 29. Shear force equation for segment AB. * O a. 0.49KN-0.15x2 (KN/m2) O b. 0.49KN-0.16x2 (KN/m2) O…

A: given beam

Q: -5.37 5 KN 6.62- -4.29- -5.02- 4 KN 3.73 3.24 E 1.04 6.2 KN B. 1.96 0.43 C 4 KN 2.4 KN -2.59 5.77-…

Q: Determine the internal force carried by member BC. 50 kN 50 kN 100 kN D. 4 m B 3 m

Q: H.W. Determ at pins Ans: A Ay D %3D %3D

A: Solution Given Data

Q: P = 10 1.5P KN P KN- A 1.5 m a. 37.5 kN/m b. 21.3 kN/m c. 20.6 kN/m d. 21.9 kN/m GH -3 m -3 m E PS…

Q: Determine the max moment

Q: 600 KN 240 KN E 16m A B 12m 12m 12m 300 KN 12) Determine the reaction at B. * 715.00 KN 751.20 KN…

Q: DRAW V AND M FOR THE BEAM LOADED AS SHOWN BELOW. 0 AN/m AN/n s0 AN kN.m D 0.75 0.75 m 0.75 m 0.75 m…

A: ∑MC=0 50 x 2 + 75 - RD x 4 + 30 x 2 x 5 = 0 RD = 118.75 kN ∑MA=0 -12×30×2×13×2 + 50×0.75 + 30×3×3 +…

Q: Determine the resultant moment about points A and B, if Fc = 17 kN, L=8 ft and M = 63 kN-ft A L Fe L…

A: Given data:

Q: 1. Equivalent resultant force. 150 kN b) 110 a) kN c) 90 kN Equivalent resultant moment about the…

A: a: equivalent resultant force:∑FY=0-30-60-40+20+R=0R=110 KN

Q: Derive the shear force equation,bending moment equation for the beam own. Neglect the weight of the…

A: Uniformly varying load with 2.1kN/m at 7 m span. To calculate shear force and bending moment…

Q: In the figure shown. find the necessary width (b), of the concrete dam to prevent the dam from…

A: Step 1: Draw a free body diagram of forces involved Step 2: Solve for horizontal and vertical…

Q: Situation G. The portal frame is loaded as shown 18. Approximately, which of the following 5kN most…

Q: P = 10 1.5P KN- P KN- F 1.5 m GH -3 m E 1.5 m, IC D 2m 6 m

A: To find force in member EF

Q: P = 10 1.5P kN- PKN- F 1.5 m, GH -3 m E -3m- 1.5 m, IC -3 m D ++ B 2m 6 m

A: P=10kN To find moment about point A

Q: 60 kN 40 kN/m 120 kN • m B - 3 m- Im--Im- 10. Find the maximum shear force. a. 72 kN b. 48 kN c. 132…

Q: Determine the internal force system acting on section 1 by analyzing the FBD o (a) segment AD and…

Q: A cantilever beam, 6m long, fixed at point A and free at point B, is subjected to a downward uniform…

Q: For W1=8.9 KN/m, W2=5 KN/m, the resultant of applied loads is WI KN/m W2 KN/m Select one: OA 36.70…

Q: Determine the force in member CD. H 3 m C E -2 m 2 m 2 m- 2 m 2 m 2 m- 4 kN 5 kN 6 kN 8 kN O 12.0 kN…

Q: 40 kN

Q: Q3 50 kN 5 m 5 m. A'nalyze the above symmetrical otructure under the given symmetrical looding by…

A: Solution Draw the diagram with reaction

Q: 600 KN 240 KN 16m A F В 12m 12m 12m 300 KN 9) Find the force in member DE. 25 KN

Q: F7-4. Determine the normal force, shear force, and moment at point C. |12 kN 9 kN/m |C -1.5 m-1.5 m…

A: F7-4. Draw the free-body diagram of the given beam. Write the equilibrium equation for the sum of…

Q: * wh шд. I 10 kN/m 15 kN/m

A: Equivalent Load The equivalent dynamic bearing load, P, is what's employed in the formulae for…

Q: PROBLEM 4 The beam shown is loaded with the triangular, rectangular and the 10kN point load. Find…

A: Give data Find resultant of loading diagram. Concept

Q: F1 = 3 kN F2 = 11 kN ৪ = 60° - 30° C. F3 = 2 kN A B 2 m 7 m F4 = 20 kN D El 30° F5 = 2 kN 1] What is…

A: 1) Resultant Moment about point B = - 3 sin60o x 5 + 20 x 2 - 2 cos30o x 5 + 2 sin30o x 2…

Q: 30. Bending moment equation for segment AB. O a. 0.58x(KN)-0.16x3(KN/m2) O b.…

A: Draw the free body diagram. Equilibrium of horizontal forces, ∑Fx=0Ax=0

Q: Compute the force in member BD in kN. P1=101kN, P2=147 kN and x = 5.9 m. Write numerical value only…

A: The 2D structure is said to be in equilibrium when it fulfills three equilibrium conditions: Sum of…

Q: Solve for the maximum shear and maximum moment of the simply supported beam. Show the shear and…

A: To determine the maximum shear and bending moment of the beam and also draw the SFD and BMD.

Q: a. Slope 8A b. Slope Oc c. Deflection Ac d. Deflection AE e. Maximum deflection between support 10…

A: Given:Required:Slope at ASlope at CDeflection at CLet us solve this by moment area method as not…

Q: 20 EN 20LN 15 KN 15KN SEN 10 EN SEN 301m - 3 m D - 60 3m = 18

Q: Derive the shear force equation,bending moment equation for the beam own. Neglect the weight of the…

A: Determine the support reactions. The sum of moments of all the forces about Point A is zero.…

Concept explainers

System of Forces

A force is an external influence or agent that changes the state of a system. According to Newton's second law, the force applied to a body is proportional to the change in momentum of a body. Hence, whenever a force is applied to a body, its momentum changes. If the body is at rest, under the action of force, its state of rest changes to motion. In other words, the magnitude of the momentum of the body changes from zero to a measurable value. Similarly, if the body possesses some initial velocity, it has some associated momentum, the effect of force can cause the body to halt or come to rest, that is, the momentum reduces to zero.

Question

FROM THE FIGURE

1. Determine the force in member AB.

a. -3.12 kN

b. -9.31 kN

c. -2.36 kN

d. -4.46 kN

2. Determine the force in member AC.

a. -5.192 kN

b. -2.362 kN

c. -1.521 kN

d. -3.722 kN

3. Determine the force in member AD.

a. 3.173 kN

b. 1.194 kN

c. 2.313 kN

d. 1.943 kN

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

SEE SOLUTION Check out a sample Q&A here

Step 1 Represent FAB in cartesian vector form

VIEW

Step 2 Represent FAC in cartesian vector form

VIEW

Step 3 Represent FAD in cartesian vector form

VIEW

Step 4 Use equillibrium condition

VIEW

Step 5 Solve each term separately

VIEW

Step 6 Solving the equation

VIEW

Step by step

Solved in 6 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, civil-engineering and related others by exploring similar questions and additional content below.

Similar questions

A 9-m simply supported beam is to carry a uniformly distributed load of 15 KN/m all throughout its length. 34. Determine the maximum shear occurring on the beam. a. 72.5 kN c. 77.5 kN b. 62.5 kN d. 67.5 kN 35. The distance of the point of zero shear from the left support is most likely equal to: a. 5.0 m c. 4.5 m b. 5.125 m d. 3.675 m 36. Maximum moment of the beam is most likely equal to: a. 162.4 kN.m b. 140.5. kN.m c. 151.9 kN.m d. 145.6 kN.m 37. Determine the shear at a point 2 m from left support: a. 42.5 kN c. 52.5 kN b. 37.5 kN d. 36.5 kN
20 KN 20 KN ACTIVITY 3 20 KN 10 KN/m 10 KN/m A B PROBLEM 1 20 KN/m TTTT 10 KN/m + C Compute the 10 KN-m 10 KN/m 10 KN/m E F G 10 KN/m reactions at the fixed şupport of Beam KL 10 KN/m K 20 KN/m 1.00 1.00 2.00 1.50 1.00 1.00 1.00 1.00 4.00 All dimensions in meters 0.50
at support D, what is the value of negative shear? a. -40 kN b. -50 kN c. -55 kN d. -60 kN at support D, what is the value of positive shear? a. 20 kN b. 25 kN c. 30 kN d. none of the above
What is the positive max. moment at span AB? a. 25.80 kN-m b. 20.80 kN-m c. 23.80 kN-m d. 15.373 kN-m The positive maximum moment at span AB is located at a distance of _________ from support A. a. 2.50 m b. 1.203 m c. 2.056 m d. 1.503 m
DRAW THE V AND 2 1100KN 4 8.0 M DIAG. OF THE 75 KN 2 S BEAM LOADED 30 kN/m 60m As sWOWN.
what is the shear at point B? a. 14 kN b. 0.58 kN c. 0.14 kN d. 1.4 kN what is the shear at point C? a. -6.14 kN b. 5.86 kN c. -4.86 kN d. -5 kN
7. Which of the following most nearly gives the maximum shear? a. 24 kN c. 96 kN b. 48 kN d. 72 kN 8. Which of the following most nearly gives the maximum moment? a. 24 kN-m c. 48 kN-m b. 84 kN-m d. 42 kN-m 9. Which of the following most nearly gives the distance from left of a point where moment is zero? a. 3.50 m c. 4.00 m b. 3.00 m d. 2.50 m 1m 112 kN/m 1.50 m 2m 112 kN/m 1.50 m 1m a
Refer to the beam below: 5m 11. Determine the degree of indeterminacy. а. 1 с. 2 b. 3 d. 6 12. If a uniform load of 15 kN/m will be loaded on the beam, compute for the maximum shear. a. 37.5 kN c. 31.25 kN b. 75 kN d. 62.5 kN 13. If a uniform load of 15 kN/m will be loaded on the beam, compute for the maximum moment. a. 37.5 kN. m C. 31.25 kN. m b. 75 kN. m d. 62.5 kN. m 14. If a uniform load of 15 kN/m will be loaded on the beam, compute for the maximum deflection. a. 48.82E1 b. 24.21EI c. 3125 EI d. 195.3125 EI 15. If an additional concentrated load of 50 kN will be loaded at the midspan, what would be the maximum moment of the beam? a. 37.5 kN. m c. 31.25 kN. m b. 75 kN. m d. 62.5 kN. m
Determine (a) the equations of the shear and bending momentcurves for the beam and loading shown (1-5), (b) draw the shearand bending moment curves for the beam and loading shown, (c) themaximum absolute value of the shear and bending moment. F1= 38 kN w1= 14 kN/m
neeed so much fast P = 10
Q1 /Draw S.F.D and B.M.D 60 KN/m 20 KN/m 100 KNm 3m 3m 1m3B Shear Force Diagram S.F.D B.M.D