5ai) Use the Newton-Raphson process to determine a value of x near x1 = 0 for which f(x) = 0, where f(x) = -5 x-0.7+4 sin (x) giving your answer (and the interim results we ask for) correct to 5 decimal places. What is the initial value of f(x)? f(x,) = ii)What are the values of x and f(x) at the second iteration? Please enter your answers as a list [in square brackets] (as per the prompt below). [X2, f(x2)] = iii)What are the values of x and f(x) at the third iteration? Please enter your answers as a list [in square brackets] (as per the prompt below). [Xs, f(x;)] = iv)The value of x (correct to 5 decimal places) such that f(x) = 0. Xfinal =

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
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5ai) Use the Newton-Raphson process to determine a value of x near x1 = 0 for which
f(x) = 0, where
f(x) = -5 x-0.7+4 sin (x)
giving your answer (and the interim results we ask for) correct to 5 decimal places.
What is the initial value of f(x)?
f(x,) =
ii)What are the values of x and f(x) at the second iteration?
Please enter your answers as a list [in square brackets] (as per the prompt below).
[X2, f(x,)] =
iii)What are the values of x and f(x) at the third iteration?
Please enter your answers as a list [in square brackets] (as per the prompt below).
[X3, f(x;)] =
iv)The value of x (correct to 5 decimal places) such that f(x) = 0.
Xfinal =
Transcribed Image Text:5ai) Use the Newton-Raphson process to determine a value of x near x1 = 0 for which f(x) = 0, where f(x) = -5 x-0.7+4 sin (x) giving your answer (and the interim results we ask for) correct to 5 decimal places. What is the initial value of f(x)? f(x,) = ii)What are the values of x and f(x) at the second iteration? Please enter your answers as a list [in square brackets] (as per the prompt below). [X2, f(x,)] = iii)What are the values of x and f(x) at the third iteration? Please enter your answers as a list [in square brackets] (as per the prompt below). [X3, f(x;)] = iv)The value of x (correct to 5 decimal places) such that f(x) = 0. Xfinal =
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