59.6 g of chromium (III) oxide were formed from reaction of 25.0 g of O₂ and excess chromium metal. What was the percent yield of this reaction. The formula mass of Cr₂O3 is 156.0 g/mol. 4 Cr(s) + 3 O₂(g) → 2 Cr₂O3(s) Enter a numerical value for your answer; omit the units of %. Your answer should have three significant figures. Do NOT enter the decimal form of the percentage.

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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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**Problem: Percent Yield Calculation in Chromium (III) Oxide Reaction**

59.6 g of chromium (III) oxide were formed from the reaction of 25.0 g of O₂ and excess chromium metal. What was the percent yield of this reaction? The formula mass of Cr₂O₃ is 156.0 g/mol.

**Chemical Equation:**

\[ 4 \text{Cr}(s) + 3 \text{O}_2(g) \rightarrow 2 \text{Cr}_2\text{O}_3(s) \]

**Instructions:**

Enter a numerical value for your answer, omitting the units of %. Your answer should have three significant figures.

Do NOT enter the decimal form of the percentage.
Transcribed Image Text:**Problem: Percent Yield Calculation in Chromium (III) Oxide Reaction** 59.6 g of chromium (III) oxide were formed from the reaction of 25.0 g of O₂ and excess chromium metal. What was the percent yield of this reaction? The formula mass of Cr₂O₃ is 156.0 g/mol. **Chemical Equation:** \[ 4 \text{Cr}(s) + 3 \text{O}_2(g) \rightarrow 2 \text{Cr}_2\text{O}_3(s) \] **Instructions:** Enter a numerical value for your answer, omitting the units of %. Your answer should have three significant figures. Do NOT enter the decimal form of the percentage.
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