57. What volume of a 0.2089 M KI solution contains enough KI to react exactly with the Cu(NO3)2 in 43.88 mL of a 0.3842 M solution of Cu(NO3)2? 2Cu(NO3)2 + 4KI → 2Cul + 12 + 4KNO,
57. What volume of a 0.2089 M KI solution contains enough KI to react exactly with the Cu(NO3)2 in 43.88 mL of a 0.3842 M solution of Cu(NO3)2? 2Cu(NO3)2 + 4KI → 2Cul + 12 + 4KNO,
Chemistry: Principles and Reactions
8th Edition
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:William L. Masterton, Cecile N. Hurley
Chapter3: Mass Relations In Chemistry; Stoichiometry
Section: Chapter Questions
Problem 24QAP: Twenty-five mL of a 0.388 M solution of Na2SO4 is mixed with 35.3 mL of 0.229 M Na2SO4. What is the...
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![57. What volume of a 0.2089 M KI solution contains enough KI to react exactly with the Cu(NO3)2 in 43.88 mL of
a 0.3842 M solution of Cu(NO3)2?
2Cu(NO3)2 + 4KI → 2Cul + I2 + 4KNO,](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8a397443-b0c2-4bec-95e2-d032d520b19e%2F2c64b89d-3252-48dd-9ddf-d6568310f976%2Fs1bw6qbl_processed.jpeg&w=3840&q=75)
Transcribed Image Text:57. What volume of a 0.2089 M KI solution contains enough KI to react exactly with the Cu(NO3)2 in 43.88 mL of
a 0.3842 M solution of Cu(NO3)2?
2Cu(NO3)2 + 4KI → 2Cul + I2 + 4KNO,
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