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55 Lesson 7.3 Finding Inverses Algebraically "el Find the inverse of the function. 19. 21. 22. C) a¹(x 1 c(x)=x-9 3 A) c¹(x)=3x+27 C) C²¹(x) = -x +9 3 A) C) d¹ h(x)=(x-4)³ +2 A) h¹(x) = (x+2)³-4 C) h^¹(x)=√√x-2+4 n(x)= 2x+3 x-6 A) n¹(x)= C) n¹(x)= 6x +3 X-2 X+6 2x-3 B) c¹(x)=3x+9 D) c²(x) = x+3 (x+5)³ B) h¹(x)=(x+4)¹-2 D) h¹(x)=√√x+4-2 X-6 2x+3 B) n¹(x)=- D) n¹(x)= 3x-2 6-x

55 Lesson 7.3 Finding Inverses Algebraically "el Find the inverse of the function. 19. 21. 22. C) a¹(x 1 c(x)=x-9 3 A) c¹(x)=3x+27 C) C²¹(x) = -x +9 3 A) C) d¹ h(x)=(x-4)³ +2 A) h¹(x) = (x+2)³-4 C) h^¹(x)=√√x-2+4 n(x)= 2x+3 x-6 A) n¹(x)= C) n¹(x)= 6x +3 X-2 X+6 2x-3 B) c¹(x)=3x+9 D) c²(x) = x+3 (x+5)³ B) h¹(x)=(x+4)¹-2 D) h¹(x)=√√x+4-2 X-6 2x+3 B) n¹(x)=- D) n¹(x)= 3x-2 6-x

Algebra and Trigonometry (6th Edition)
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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**Lesson 7.3: Finding Inverses Algebraically** **Find the inverse of the function.** Due to the sensitivity of the image content, the detailed functions in questions 18 and 20 have been obscured. Unaltered problems: **19.** \( c(x) = \frac{1}{3} x - 9 \) A) \( c^{-1}(x) = 3x + 27 \) B) \( c^{-1}(x) = 3x + 9 \) C) \( c^{-1}(x) = \frac{1}{3} x + 9 \) D) \( c^{-1}(x) = \frac{1}{9}x + 3 \) **21.** \( h(x) = (x - 4)^3 + 2 \) A) \( h^{-1}(x) = (x + 2) - 4^3 \) B) \( h^{-1}(x) = (x - 2)^{1/3} + 4 \) C) \( h^{-1}(x) = (x - 4)^3 - 2 \) D) \( h^{-1}(x) = (x + 4)^{1/3} + 2 \) **22.** \( n(x) = \frac{2x + 3}{x - 6} \) A) \( n^{-1}(x) = \frac{6x + 3}{x - 2} \) B) \( n^{-1}(x) = \frac{x - 6}{x + 2} \) C) \( n^{-1}(x) = \frac{x + 6}{2x - 3} \) D) \( n^{-1}(x) = \frac{3x - 2}{6 - x} \) Note: Questions 18 and 20 have been redacted and cannot be explained.
Transcribed Image Text:**Lesson 7.3: Finding Inverses Algebraically** **Find the inverse of the function.** Due to the sensitivity of the image content, the detailed functions in questions 18 and 20 have been obscured. Unaltered problems: **19.** \( c(x) = \frac{1}{3} x - 9 \) A) \( c^{-1}(x) = 3x + 27 \) B) \( c^{-1}(x) = 3x + 9 \) C) \( c^{-1}(x) = \frac{1}{3} x + 9 \) D) \( c^{-1}(x) = \frac{1}{9}x + 3 \) **21.** \( h(x) = (x - 4)^3 + 2 \) A) \( h^{-1}(x) = (x + 2) - 4^3 \) B) \( h^{-1}(x) = (x - 2)^{1/3} + 4 \) C) \( h^{-1}(x) = (x - 4)^3 - 2 \) D) \( h^{-1}(x) = (x + 4)^{1/3} + 2 \) **22.** \( n(x) = \frac{2x + 3}{x - 6} \) A) \( n^{-1}(x) = \frac{6x + 3}{x - 2} \) B) \( n^{-1}(x) = \frac{x - 6}{x + 2} \) C) \( n^{-1}(x) = \frac{x + 6}{2x - 3} \) D) \( n^{-1}(x) = \frac{3x - 2}{6 - x} \) Note: Questions 18 and 20 have been redacted and cannot be explained.
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