53: What sorting algorithm is this? void Sort1(string arr[), int beg, int end) { int piv index = subdivision(arr, beg, end); if (piv_index-1 > beg) { Sort1(arr, beg,piv_index-1); } if (piv_ind+1 < end) { Sort1(arr,piv_index+1, end); } int subdivision(string arr[],int beg, int end) ( int up = beg; int down = end; string tmp. string piv = arr[up]; up += 1; while (up <= down) { while (arr[up] < piv) up++; while (arr[down] > piv) down--; if (up <= down) { tmp = arr(up]; arr[up] = arr[down]; arr[down] tmp; up++; down--; } } arr[beg] = arr[down]; arr[down] = piv; return down;

53: What sorting algorithm is this? void Sort1(string arr[), int beg, int end) { int piv index = subdivision(arr, beg, end); if (piv_index-1 > beg) { Sort1(arr, beg,piv_index-1); } if (piv_ind+1 < end) { Sort1(arr,piv_index+1, end); } int subdivision(string arr[],int beg, int end) ( int up = beg; int down = end; string tmp. string piv = arr[up]; up += 1; while (up <= down) { while (arr[up] < piv) up++; while (arr[down] > piv) down--; if (up <= down) { tmp = arr(up]; arr[up] = arr[down]; arr[down] tmp; up++; down--; } } arr[beg] = arr[down]; arr[down] = piv; return down;

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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A: Here is the solution with an output:-

Question

53: What sorting algorithm is this?
void Sort1(string arr[], int beg, int end) {
int piv index = subdivision(arr, beg, end);
if (piv_index-1 > beg) {
Sort1(arr, beg, piv_index-1);
}
if (piv_ind+1 < end) {
Sort1(arr, piv_index+1, end);
}
}
int subdivision (string arr[], int beg, int end) {
int up = beg;
int down = end;
string tmp.
string piv = arr[up];
up += 1;
while (up <= down) (
while (arr[up] < piv)
up++;
while (arr[down] > piv)
down--;
if (up <= down) {
tmp = arr[up];
arr[up] = arr[down];
arr[down] = tmp;
up++;
down --;
}
arr[beg] = arr[down];
arr[down] = piv;
return down;
%3D

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