i need help w f-g Exam 1-practiceVi=0 misa.= ?11152. The National Sleep Foundation reported that 36.8% of all adults snore. Of the people who snore,87% are over the age of 30. 81.5% of people in their study were over the age of 30.(a) Write the above statements in probability notation.(b) Find the probability that someone is over 30 and snores.(c) Find the probability that someone is over 30 or snores.(d) Given someone is over 30, what is the probability that he or she snores?lobe) What is the probability that someone does not snore?(f) Are snoring and being over 30 mutually exclusive events? Explain with probabilities.(g) Are snoring and being over 30 independent events? Explain with probabilities.

Answered: 52. The National Sleep Foundation…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

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Section: Chapter Questions

Problem 1P

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i need help w f-g

Exam 1-practice
Vi=0 mis
a.= ?
111
52. The National Sleep Foundation reported that 36.8% of all adults snore. Of the people who snore,
87% are over the age of 30. 81.5% of people in their study were over the age of 30.
(a) Write the above statements in probability notation.
(b) Find the probability that someone is over 30 and snores.
(c) Find the probability that someone is over 30 or snores.
(d) Given someone is over 30, what is the probability that he or she snores?
lobe) What is the probability that someone does not snore?
(f) Are snoring and being over 30 mutually exclusive events? Explain with probabilities.
(g) Are snoring and being over 30 independent events? Explain with probabilities.

Expert Solution

Step 1

Two events can be said mutually exclusive, if they cannot happen at the same time. It is mentioned that events $A$ and $B$ are mutually exclusive, it means they both cannot happen at the same time. This implies, $P (A \cap B) = 0$ .

If happening/not happening of one event does not affect the happening/not happening of other event, then such events can be termed as independent events. If $A$ and $B$ are two independent events, then $P (A \cap B) = P (A) \cdot P (B)$ .