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The Electric Field E to be created by the point charge Q = variable7 nC placed at the point P (7, -4, -1) at the point T (-9, -7, 10) is given below. Find the values of K, L and M accordingly. TT=3,1416 3бт.10 E =K âz+ Lây+ Mâz K= M=

The Electric Field E to be created by the point charge Q = variable7 nC placed at the point P (7, -4, -1) at the point T (-9, -7, 10) is given below. Find the values of K, L and M accordingly. TT=3,1416 3бт.10 E =K âz+ Lây+ Mâz K= M=

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P(7, -4, -1) noktasında bulunan Q=107,5 nC 'luk yükün T(-9, -7, 10) noktasında oluşturacağı Elektrik Alan E aşağıda verilmiştir. Buna göre K, L ve M değerlerini bulunuz. The Electric Field E to be created by the point charge Q = variable7 nC placed at the point P (7, -4, -1) at the point T (-9, -7, 10) is given below. Find the values of K, L and M accordingly. TT=3,1416 -9 3бл.10 E =K âg+ Lây+ M âz K= M=
Transcribed Image Text:P(7, -4, -1) noktasında bulunan Q=107,5 nC 'luk yükün T(-9, -7, 10) noktasında oluşturacağı Elektrik Alan E aşağıda verilmiştir. Buna göre K, L ve M değerlerini bulunuz. The Electric Field E to be created by the point charge Q = variable7 nC placed at the point P (7, -4, -1) at the point T (-9, -7, 10) is given below. Find the values of K, L and M accordingly. TT=3,1416 -9 3бл.10 E =K âg+ Lây+ M âz K= M=
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i have sent this question 2 times and  " Expert" solve it wrong even diffrent result  as show in photos, so could you tell me which way is coorect and if neither of them incorrect could you solve it again with ditailed and easy way.

Thank you 

 

9x10° (N_m²/C²)x7x10- (C) ((-9â,-Tâ,+10â)-(7â¸-4€â,₁))|²³ 63(NIC) (-160,-3a,+11a) 63(NIC) (-16)²+(-3)²+(11)² =-51.306ax - 9.62ây + 35.273âz ((–9ây – Tây + 10az) - (Tây – tây - a)) (²³) (m) (-16ax - 3ây + 11â₂) (-16âx - 3ầy + 11â₂)
Transcribed Image Text:9x10° (N_m²/C²)x7x10- (C) ((-9â,-Tâ,+10â)-(7â¸-4€â,₁))|²³ 63(NIC) (-160,-3a,+11a) 63(NIC) (-16)²+(-3)²+(11)² =-51.306ax - 9.62ây + 35.273âz ((–9ây – Tây + 10az) - (Tây – tây - a)) (²³) (m) (-16ax - 3ây + 11â₂) (-16âx - 3ầy + 11â₂)
Therefore, E = I 45²0 16² I 7x10-⁹ + 17x10⁹ 4². 11² 4x²0 7x10-⁹ 7x10-9 7x10⁹ E = + + 4xx36xx10²x256 4xx36xx10³x9 4xx36x10³x121 7 7 7 E = + + 363464.29 12778.0416 171793.67 E = 0.000001925ax +0.0005478ẩy + 0.0000407465az E = 0.1925ax + 5.4ay+0.407a₂ Step 4 Conclusion: E = 0.1925a + 5.4ay+0.407az K = 0.19 L = 5.4 M = 0.4 7x10-⁹ 3² +
Transcribed Image Text:Therefore, E = I 45²0 16² I 7x10-⁹ + 17x10⁹ 4². 11² 4x²0 7x10-⁹ 7x10-9 7x10⁹ E = + + 4xx36xx10²x256 4xx36xx10³x9 4xx36x10³x121 7 7 7 E = + + 363464.29 12778.0416 171793.67 E = 0.000001925ax +0.0005478ẩy + 0.0000407465az E = 0.1925ax + 5.4ay+0.407a₂ Step 4 Conclusion: E = 0.1925a + 5.4ay+0.407az K = 0.19 L = 5.4 M = 0.4 7x10-⁹ 3² +
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could you write it on peaper because i coulod read like this

 

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