____ yr A sample from a meteorite that landed on Earth has been analyzed, and the result shows that out of every 1,000 nuclei of potassium-40 originally inthe meteorite, only 250 are still present, meaning they have not yet decayed. How old is the meteorite (in yr)? (Hint: See the figure below.) (Note:The half-life of potassium-40 is 1.3 billion years.)FigureGraphBar chartsA mineral samplecontaining radioactiveatoms :, which decayinto daughter atoms ::100Percentage ofradioactive and50daughter atomsin the mineral100Percentage of50radioactive atomsremaining12346Age in half-livesyrPercentage remaining---1/2 remain----E1/4 remain---- ---ల1/8 remain-T-- -

A sample from a meteorite that landed on Earth has been analyzed, and the result shows that out of every 1,000 nuclei of potassium-40 originally in the meteorite, only 250 are still present, meaning they have not yet decayed. How old is the meteorite (in yr)? (Hint: See the figure below.) (Note: The half-life of potassium-40 is 1.3 billion years.) The initial number of particles of potassium-40 is given as, No=1000. The number of particles present now is given as, N=250. The half-life of potassium-40 is given as, t1/2=1.3 billion years (or) t1/2=1.3×109 yrs. TO DETERMINE: (a) The age of the Meteorite in years, t.From radioactive decay equation, we have, N=Noe-λt --------------- (1) Where, No is the initial (original) number of particles, N is the remaining number of particles, λ is the decay constant, t is the age of the object. Rearranging above equation, we have, e-λt=NNo Taking natural log on both sides, we have, -λt=lnNNo (or) t=-lnN/Noλ --------------------- (2) Using equation (2), we can calculate the age of meteorite.The decay constant is calculated using the formula, t1/2=ln2λ ---------------- (1) Rearranging above equation, we have, λ=ln2t1/2 -------------------- (2) Substituting the values in equation (2), we have, λ=0.6931.3×109 λ=0.533×10-9 /yr.(a) The age of the Meteorite in years, t: The age of the meteorite can be calculated using the formula, t=-lnN/Noλ ----------------- (1) Substituting the values in equation (1), we have, t=-ln125/10000.533×10-9 t=-ln0.1250.533×109 t=--2.07940.533×109 The age of the meteorite can be calculated as, t=3.9×109 yrs (or) t=3.9 billion years.(a) The age of the Meteorite in years, t is calculated as, t=3.9×109 yrs (or) t=3.9 billion years.

Answered: A sample from a meteorite that landed…