CRACK ANALYSIS OF REINFORCED CONCRETE Determine the ffa.) Mmax in KNMb.) Ig in *loʻmmC.) fc m MPad.)in MPae.) fs' m MPaf.) Icr in X 10°mmg.) n SITUATION I210 KN70mm000-03.5m4-#8IS KN/MGm營5mA3- #6SPECS :• fc'= 32MPA= 415 MPa• fy%3D-0-O-060mm300 mmCROSS -SECTION FROMPOINT A to C500mm

Note: As per the company policy, only three sub-parts will be answered at a time. Since, it is not…

Answered: 500mm ✪-0-0- 4-#8 3-#6 -0--0- 300mm…

500mm ✪-0-0- 4-#8 3-#6 -0--0- 300mm 70mm [60 60mm → CROSS-SECTION FROM POINT A to C 210 KN 3.5m 15 kr/m com o SPECS: 5m • fc¹= 32MPa • fy = 415 MPa

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Concept explainers

Fluid Materials

In general terms, anything that flows can be termed as a fluid. In other words, a fluid is any substance that cannot resist shear forces and deforms continuously under the application of external shear forces. Fluid materials differ completely from solid materials such as metals and alloys. For instance, if we consider two infinitesimally small cross-sectional areas of fluid materials and solid materials, and apply shear forces to these elements, both the elements will undergo deformation. Upon releasing the shear force, the element of the solid materials will regain its original orientation, but the element of the fluid materials will keep on deforming continuously under the action of the shear force.

Question

CRACK ANALYSIS OF REINFORCED CONCRETE

Determine the ff
a.) Mmax in KNM
b.) Ig in *
loʻmm
C.) fc m MPa
d.)
in MPa
e.) fs' m MPa
f.) Icr in X 10°mm
g.) n

SITUATION I
210 KN
70mm
000-0
3.5m
4-#8
IS KN/M
Gm
營
5m
A
3- #6
SPECS :
• fc'= 32MPA
= 415 MPa
• fy
%3D
-0-O-0
60mm
300 mm
CROSS -SECTION FROM
POINT A to C
500mm

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