500-ft curve, grades of g1=+2.00% and g2=−2.50%, VPI at station 96+80, and elevation 845.260 ft, stakeout at full stations. Determine the elevation at the high point of the curve. Express your answer in feet to six significant figures. Determine the station at the high point of the curve.

Q: 500-ft curve, grades of g₁ = +2.50% and g₂ = -3.00%, Pl at station 96 + 80 and elevation 835.26 ft,…

A: g1=+2.5%g2= -3.00%L=500ftVPI station =96+80Elevation= 835.26ft

Q: A 500-ft curve, 9₁ = -2.00%, g2 = +3.00%, VPI station = 98+10, VPI elevation = 5388.26 ft, stakeout…

A: g1 = -2.00%g2= +3.00%L = 500ftVPI station, Elevation of VPI, To find: Elevation of full stations.

Q: 8, Horizontal Alignment Design - A horizontal curve has a deflection angle of 60 degree and a radius…

A: Radius of curve (R) = 300m Deflection angle (∆ or α) = 60°If the length of the curve is equal to…

Q: Given: L=1500 ft.; G1=+1%, G2=+4%; What is the change in elevation from a point on the incoming…

A: L = 1500ft G1 = +1% G2 = +2%   It has been asked in the question to determine the change in…

Q: Given a transition curve length of 85.500m, a design radius of 620.000m, a deflection angle of 95…

A: GIVEN DATA, Length of the  transition curve (l)= 85.5m design radius of the curve (R) = 620 m…

Q: An equal-tangent sag curve of length 920ft needs to be designed for 55 mph to connect an initial…

A: Given:- The length of the sag curve = 920 ft The design speed = 55 mph The initial downgrade = 5%…

Q: A 500-ft curve, grades of g₁-3.50% and 92-1.75%, VPI at station 38+00, and elevation 560.00 ft,…

A: A sag valley curve is given with Grade, g1 =-3.50% and g2 = -1.75%  VPI = 38+00  Elevation = 560 ft…

Q: A 500-ft curve, g₁ = -2.00%, 92 = +3.00%, VPI station = 98 + 10, VPI elevation = 5388.26 ft,…

A:

Q: Given: L = 20 stations, G1=-2%,G2=+1%; The elevation difference from the PC to the low point of the…

A: The Elevation difference from PC to low point of curve is given by ; X X = g1 LA where ; g1 = -2 % L…

Q: A 500-ft curve, grades of g₁ = +2.50% and 9₂ = -3.00%, VPI at station 96 + 80 and elevation 835.26…

A:

Q: 3.3 Vertical Alignment 53 ELEMENTS OF VERTICAL CURVE DESIGN An equal-tangent vertical curve is to be…

A: I have tried to solve this problem and also write the given data in diagram plz have gone through it

Q: A +3% grade meets a -2% grade at station 60+50 and elevation 850.25ft, 1000 ft curve, stakeout at…

A: In transportation engineering or survey, the curve is classified as horizontal and vertical curves,…

Q: Vertical highway curve: Given PVI at 128 + 00, L = 1,000 ft, g1 = -5%, g2 = +4%, and PVI elevation =…

A:

Q: you have determined the curve to be 1100 ft long. Now, you need to when the BVC is located at…

A:

Q: Design a vertical curve connecting PVI₁ (station = 4+980, Elevation = 198 m), PVI₂ (station = 5+990,…

A: PVI₁ (station = 4+980, Elevation = 198 m) PVI₂ (station = 5+990, Elevation = 163 m) and PVI₃…

Q: A +1.512% grade meets a -1.785% grade at PVI Station 31+50, elevation 562.00. The Equal Tangent…

A: Given:- The initial grade of the curve = +1.512% The final grade of the curve = -1.785% The station…

Q: Determine variables requested below for a horizontal curve with the following characteristics.…

A:

Q: 2. Compute by hand and tabulate station elevations and the 1st and 2nd differences for an equal…

A: Data given G1 =+3.5% G2 =-4 % Station PVI = 12+65 Elevation PVI = 300 ft Length of curve, L = 750 ft…

Curve setting

A curve is a turn that is provided horizontally or vertically in the design of highways, railways, and runways. A curve connects two straight lines that are separated by the deflection angle. It helps to change the direction and alignment of the highways, railway tracks, and runways. Therefore, the gradual change in their alignment is made by using a curve to provide comfort to the passengers and this also provides an easy turn to change the direction of the moving vehicle.