50.0 mL of a 0.0010 M HC₂H302 (Ka = 1.8 x 105) solution is titrated with 50.0 mL 0.0010 M NaOH. What indicator should be used? Othymol blue (PKIN = 1.65) O bromthymol blue (PKIN = 7.30) O ethyl orange (pKin = 3.46) O methyl red (pKIN = 5.00) O phenolphthalein (PKIN = 8.7)
50.0 mL of a 0.0010 M HC₂H302 (Ka = 1.8 x 105) solution is titrated with 50.0 mL 0.0010 M NaOH. What indicator should be used? Othymol blue (PKIN = 1.65) O bromthymol blue (PKIN = 7.30) O ethyl orange (pKin = 3.46) O methyl red (pKIN = 5.00) O phenolphthalein (PKIN = 8.7)
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Q11
![Question 11:
50.0 mL of a 0.0010 M HC₂H302 (Ka = 1.8 x 10-5) solution is titrated
with 50.0 mL 0.0010 M NaOH. What indicator should be used?
Othymol blue (PKIN = 1.65)
O bromthymol blue (PKIN = 7.30)
ethyl orange (PKIN = 3.46)
methyl red (PKIN = 5.00)
O
phenolphthalein (PKIN = 8.7)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb4b213bd-3ec1-4acd-bb80-5fbddcaac1ab%2F463e0b42-beb4-4d6e-86d5-57f813ab50b1%2F8cphy3b_processed.png&w=3840&q=75)
Transcribed Image Text:Question 11:
50.0 mL of a 0.0010 M HC₂H302 (Ka = 1.8 x 10-5) solution is titrated
with 50.0 mL 0.0010 M NaOH. What indicator should be used?
Othymol blue (PKIN = 1.65)
O bromthymol blue (PKIN = 7.30)
ethyl orange (PKIN = 3.46)
methyl red (PKIN = 5.00)
O
phenolphthalein (PKIN = 8.7)
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Step 1: concept
pH at equivalence point during titration should fall in between indicator pH range.
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