50 KVA, 34.5 kV/380V of y/y-connected, three- phase transformer internal parameters R1= (16/10) 0/phase (R2=0.005 0/phase, X1o=18 0/phase, X20=0.01 0/phase, Xm=100 0/phase, Rf=10 kQ/phase 'dir. Power loss in the primary Pk = 500W when the secondary is short-circuited so that the

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Question:
50 KVA, 34.5 kV/380V of y/y-connected, three-
phase transformer internal parameters R1=
(16/10) Q/phase (R2=0.005 0/phase, X10=18
0/phase, X2o=0.01 0/phase, Xm=100 0/phase,
Rf=10 kQ/phase
'dir. Power loss in the primary Pk = 500W when
%3D
the secondary is short-circuited so that the
rated current passes through the primary
it's being measured. The power loss is Po =
1kW when the transformer is idle. Primary and
primary reduced secondary leakage
since their reactances are equal to each other
(X o1 = X 'o2)
a)Draw the equivalent circuit reduced to the
primary and calculate the circuit parameters.
b)At full load cosp = 0.76. Calculate yield
%3D
Transcribed Image Text:Question: 50 KVA, 34.5 kV/380V of y/y-connected, three- phase transformer internal parameters R1= (16/10) Q/phase (R2=0.005 0/phase, X10=18 0/phase, X2o=0.01 0/phase, Xm=100 0/phase, Rf=10 kQ/phase 'dir. Power loss in the primary Pk = 500W when %3D the secondary is short-circuited so that the rated current passes through the primary it's being measured. The power loss is Po = 1kW when the transformer is idle. Primary and primary reduced secondary leakage since their reactances are equal to each other (X o1 = X 'o2) a)Draw the equivalent circuit reduced to the primary and calculate the circuit parameters. b)At full load cosp = 0.76. Calculate yield %3D
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