5 The rate law for the reaction of HO-HO-with tert-butyl bromide to form anelimination product in 75%% ethanol 25%%water at 30 °COC is the sum of the rate lawsfor the E2E2 and E1E1 reactions:rate = 7.1x10-57.1×10-5 [tert-butylbromide][ HO-HO-]+1.5x10-51.5×10-5[tert-butyl bromide].What percentage of the reaction takesplace by the E2E2 pathway under thefollowing conditions?%3DHO-= 3.2 M

The rate for E1 and E2 elimination are shown as follows: rate(E1) = k1[tertiary butyl bromide]…

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Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

The rate law for the reaction of HO-HO-
with tert-butyl bromide to form an
elimination product in 75%% ethanol 25%%
water at 30 °COC is the sum of the rate laws
for the E2E2 and E1E1 reactions:
rate = 7.1x10-57.1×10-5 [tert-butyl
bromide][ HO-HO-]+
1.5x10-51.5×10-5[tert-butyl bromide].
What percentage of the reaction takes
place by the E2E2 pathway under the
following conditions?
%3D
HO-= 3.2 M

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