5.8 Consider a map data abstraction that maps Strings to ints. Maps allow an ex- isting mapping to be looked up. Maps are also mutable: new pairs can be added to a map, and an existing mapping can be removed. Give a specification for maps. Be sure your data type is adequate, and if any operations throw excep- tions, explain whether they are checked or unchecked. Also implement your specification. Give the rep invariant and abstraction function and implement repok and tostring.

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5.8 Consider a map data abstraction that maps Strings to ints. Maps allow an ex-
isting mapping to be looked up. Maps are also mutable: new pairs can be added
to a map, and an existing mapping can be removed. Give a specification for
maps. Be sure your data type is adequate, and if any operations throw excep-
tions, explain whether they are checked or unchecked. Also implement your
specification. Give the rep invariant and abstraction function and implement
repok and tostring.
Transcribed Image Text:5.8 Consider a map data abstraction that maps Strings to ints. Maps allow an ex- isting mapping to be looked up. Maps are also mutable: new pairs can be added to a map, and an existing mapping can be removed. Give a specification for maps. Be sure your data type is adequate, and if any operations throw excep- tions, explain whether they are checked or unchecked. Also implement your specification. Give the rep invariant and abstraction function and implement repok and tostring.
Expert Solution
Step 1

The first part of Map specification is done. Map is a ordered data structure where the values are ordered based on the key values. The key values can be any datatype as int or strings. There should be unique keys in map.

consider a map program in java which have string as key and integer as value.

import java.util.*;
class Main {
publicstaticvoid main(String args[])
{
Map<String, Integer> hm
= new HashMap<String, Integer>();
 
 
hm.put("a", new Integer(100));
hm.put("b", new Integer(200));
//even though d is inserted before c, map will keep the key ordering
hm.put("d", new Integer(400));
hm.put("c", new Integer(300));
System.out.println("Map generated");
 
// Traversing through the map
for (Map.Entry<String, Integer> me : hm.entrySet()) {
System.out.print(me.getKey() + ":");
System.out.println(me.getValue());
}
//remove a mapping
hm.remove("b");
System.out.println("Map after removing an element");
for (Map.Entry<String, Integer> me : hm.entrySet()) {
System.out.print(me.getKey() + ":");
System.out.println(me.getValue());
}
}
}
 
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