5.79 For the beam and loading of Prob. 5.78, determine (a) the distance a for which w = 20 kN/m, (b) the corresponding value of wg. 24 kN a=0.6 m Fig. P5.78 1.8 m - 30 kN 0.3 m B wp

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
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### Problem 5.79

#### Problem Statement:
For the beam and loading of Problem 5.78, determine:
(a) the distance \( a \) for which \( w_A = 20 \, \text{kN/m} \),
(b) the corresponding value of \( w_B \).

#### Diagram Details:
- The beam is subjected to a linearly varying distributed load and two concentrated loads.
- The distributed load starts at \( w_A \) at the left end (point A) and varies linearly to \( w_B \) at the right end (point B).
- There are two concentrated loads acting downwards: 
  - A 24 kN load located 0.6 meters from point A.
  - A 30 kN load located 0.3 meters from point B.
- The total length of the beam from point A to point B is 1.8 meters.

#### Figure Description:
- Fig. P5.78 displays the beam with the distributed and concentrated loads.
- The distributed load is represented by a series of downward arrows starting from \( w_A \) at point A and increasing linearly to \( w_B \) at point B.
- The beam is shown horizontally with designated distances for the concentrated loads and overall length:
  - The distance from point A to the point where the 24 kN load is applied is 0.6 meters.
  - The distance from point B to the point where the 30 kN load is applied is 0.3 meters.
  - The total length of the beam is 1.8 meters.

These details will help determine the distance \( a \) and the corresponding value of \( w_B \) using the principles of static equilibrium and the conditions described in the problem statement.
Transcribed Image Text:### Problem 5.79 #### Problem Statement: For the beam and loading of Problem 5.78, determine: (a) the distance \( a \) for which \( w_A = 20 \, \text{kN/m} \), (b) the corresponding value of \( w_B \). #### Diagram Details: - The beam is subjected to a linearly varying distributed load and two concentrated loads. - The distributed load starts at \( w_A \) at the left end (point A) and varies linearly to \( w_B \) at the right end (point B). - There are two concentrated loads acting downwards: - A 24 kN load located 0.6 meters from point A. - A 30 kN load located 0.3 meters from point B. - The total length of the beam from point A to point B is 1.8 meters. #### Figure Description: - Fig. P5.78 displays the beam with the distributed and concentrated loads. - The distributed load is represented by a series of downward arrows starting from \( w_A \) at point A and increasing linearly to \( w_B \) at point B. - The beam is shown horizontally with designated distances for the concentrated loads and overall length: - The distance from point A to the point where the 24 kN load is applied is 0.6 meters. - The distance from point B to the point where the 30 kN load is applied is 0.3 meters. - The total length of the beam is 1.8 meters. These details will help determine the distance \( a \) and the corresponding value of \( w_B \) using the principles of static equilibrium and the conditions described in the problem statement.
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