(5.7: Similar to For practice 5.11)The titration of a 20.0 mL sample of an H₂SO4 solution of unknown concentration requires 18.88 mL of a 0.203 M KOH to reach the equivalence point. What is the concentration (in M) of the unknown H₂SO4 solution? (Hint: Write the balanced reaction equation first.) 0.0958 M O 0.383 M O 0.767 M O 0.192 M

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**Titration Problem Example (Similar to Practice 5.11)**

In this example, we are given a problem involving the titration of a 20.0 mL sample of an H₂SO₄ solution with an unknown concentration. To reach the equivalence point, 18.88 mL of a 0.203 M KOH solution is required. Our task is to determine the concentration (in M) of the unknown H₂SO₄ solution.

**Hint: Write the balanced reaction equation first.**

**Options:**
- 0.0958 M
- 0.383 M
- 0.767 M
- 0.192 M

**Step-by-step approach:**

1. **Write the balanced reaction equation:**
   \[ \text{H}_2\text{SO}_4 (aq) + 2 \text{KOH} (aq) \rightarrow \text{K}_2\text{SO}_4 (aq) + 2 \text{H}_2\text{O} (l) \]

2. **Determine the moles of KOH used:**
   \[ \text{Moles of KOH} = \text{Volume (L)} \times \text{Molarity (M)} \]
   \[ \text{Moles of KOH} = 0.01888 \, \text{L} \times 0.203 \, \text{M} = 0.00383264 \, \text{mol KOH} \]

3. **Use the stoichiometry of the balanced equation to find moles of H₂SO₄:**
   According to the equation, 1 mole of H₂SO₄ reacts with 2 moles of KOH.
   \[ \text{Moles of H}_2\text{SO}_4 = \frac{\text{Moles of KOH}}{2} = \frac{0.00383264}{2} = 0.00191632 \, \text{mol H}_2\text{SO}_4 \]

4. **Calculate the concentration of H₂SO₄:**
   \[ \text{Concentration (M)} = \frac{\text{Moles}}{\text{Volume (L)}} \]
   \[ \text{Concentration of H}_2
Transcribed Image Text:**Titration Problem Example (Similar to Practice 5.11)** In this example, we are given a problem involving the titration of a 20.0 mL sample of an H₂SO₄ solution with an unknown concentration. To reach the equivalence point, 18.88 mL of a 0.203 M KOH solution is required. Our task is to determine the concentration (in M) of the unknown H₂SO₄ solution. **Hint: Write the balanced reaction equation first.** **Options:** - 0.0958 M - 0.383 M - 0.767 M - 0.192 M **Step-by-step approach:** 1. **Write the balanced reaction equation:** \[ \text{H}_2\text{SO}_4 (aq) + 2 \text{KOH} (aq) \rightarrow \text{K}_2\text{SO}_4 (aq) + 2 \text{H}_2\text{O} (l) \] 2. **Determine the moles of KOH used:** \[ \text{Moles of KOH} = \text{Volume (L)} \times \text{Molarity (M)} \] \[ \text{Moles of KOH} = 0.01888 \, \text{L} \times 0.203 \, \text{M} = 0.00383264 \, \text{mol KOH} \] 3. **Use the stoichiometry of the balanced equation to find moles of H₂SO₄:** According to the equation, 1 mole of H₂SO₄ reacts with 2 moles of KOH. \[ \text{Moles of H}_2\text{SO}_4 = \frac{\text{Moles of KOH}}{2} = \frac{0.00383264}{2} = 0.00191632 \, \text{mol H}_2\text{SO}_4 \] 4. **Calculate the concentration of H₂SO₄:** \[ \text{Concentration (M)} = \frac{\text{Moles}}{\text{Volume (L)}} \] \[ \text{Concentration of H}_2
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