5.68 •• CP In Fig. P5.68 Figure P5.68 m1 = 20.0 kg and 53.1°. The coefficient of a = kinetic friction between the block and the incline is µk 0.40. What must be the mass m2 of the hanging block if it is to descend 12.0 m in the first 3.00 s after the system is released from rest? m2
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- 60.A 60.0-kg skier with an initial speed of 12.0 m/s coasts up a 2.50-m high rise as shown. Find her final speed at the top, given that the coefficient of friction between her skis and the snow is 0.80. K₁ 35° V₁ = ? 2.5 m1. A 75 kg box is standing on top of a moving cart. If the coefficient of static friction between the box and the cart is 0.38, what is the maximum acceleration of the cart so that the box does not tip over or slide? 0.35 m 0.35 m • G 1.2 m aForces: A 7.60×103 kg transport truck is approaching a 20.0° icy hill that has a bridge at the top that is out of service. The driver immediately slams on the brakes and begins to skid up the hill. The coefficient of kinetic friction between the tires and the hill is 0.350. If there is only 131 m from the bottom of the hill to the bridge what maximum speed can the truck initially be going and still avoid an accident?
- A package is projected 10 m upward on a 15 ° inclined plane so that it reaches the top of the plane with zero velocity. Knowing that the coefficient of kinetic friction between the package and the incline is 0.15, determine the speed of the package when it returns to its original position.4. The goal of a worker is to slide a 20-kg crate up a 2.5 m-long inclined at 25°. The worker was confident that he can do this by giving it an initial speed of 4.5 m/s at the bottom and letting it go. However, the crate slides only 1.7 m up the ramp, stops, and slides back down. Find the magnitude of the friction force acting on the crate and its velocity when it reaches the bottom of the ramp again.The 54-kg crate is projected down an incline as shown with an initial speed of 7.8 m/s. Investigate the time t required for the crate to come to rest and the corresponding distance x traveled if 0 = 11.2°. What is the largest angle for which the block will stop? %=7.8 m/s 1500 54 kg - Hik m i S, X= 0.50 Answers 0=11.2°, t= i emax = i 0
- WE-4 A 3.00kg block is initially sliding to the right on P (N) 20 a frictionless surface at 7.00m/s. Force P is directed to the left and is applied to the block continuously starting at the initial position as shown below. The magnitude of P varies as shown in the graph to the right. V=7.00m/s 15 10 5. 0 1 2 3 4 (m) a) Find the magnitude of the work done by the force P as the block moves from x-0 to x=4m. b) Find the kinetic encrgy of the block at x-4m. Neglect air resistance (and the surface is frictionless). c) Find the speed of the block at x-4m. P Type here to search %23 直5. Two identical blocks, each with mass m, both at rest initially, are connected, as shown. The surface is rough with the coefficient of kinetic friction 4. If the initial height is h, what are the speeds of the blocks once the hanging block hits the ground? h1. A 10.0-kg block is pushed up a 30• inclined plane that is 10.0 m long starting from rest. The coefficient of kinetic friction between the block and the plane is uk = 0.20. What is the magnitude of the constant force required to move the block from the bottom of the plane to the top in 3.00 s?
- 4.35 •• Two adults and a child want to push a wheeled cart in the direc- tion marked x in Fig. P4.35 (next page). The two adults push with hori- zontal forces É and F, as shown. (a) Find the magnitude and direction of the smallest force that the child should exert. Ignore the effects of friction. (b) If the child exerts the minimum force found in part (a), the cart ac- celerates at 2.0 m/s- in the +x-direction. What is the weight of the cart?Problem 6: A4.8 • 105-kg rocket is accelerating straight up. Its engines produce 1.35 • 107 N of thrust, and air resistance is 4.7. 106 N. Randomized Variables m = 4.8. 105-kg f=1.35.107 N fr=4.7.106 N. What is the rocket's acceleration, using a coordinate system where up is positive? a = sin() cos() cotan() asin() atan() acotan() cosh() tanh() O Degrees tan() J ( acos() E M sinh() / cotanh() Radians * 7 4 1 - 8 9 5 6 2 3 + 0 VO BACKSPACE HOME END DEL CLEAR