5.4.19-TQuestion HelpThe heights of fully grown trees of a specific species are normally distributed, with a mean of 70.5 feet and a standard deviation of 6.25 feet. Random samples of size 11 are drawn from the population. Use the central limit theoremto find the mean and standard error of the sampling distribution. Then sketch a graph of the sampling distribution.The mean of the sampling distribution is u; =%3DThe standard error of the sampling distribution is o; =-(Round to two decimal places as needed.)Enter your answer in the edt fields and then click Check Answer1 ParttemainingClear AllOVI 12:55hpesc#3&backspace6.3Уtabenterd.shift* 00

Answered: Image /qna-images/answer/b3b383a6-2f0d-4dc3-a011-96b99eeaa715.jpg

Answered: 5.4.19-T Question Help The heights of…

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

See similar textbooks

Similar questions

please see image
Previously, De Anza's statistics students estimated that the amount of change daytime statistics students carry is exponentially distributed with a mean of $0.88. Suppose that we randomly pick 25 daytime statistics students. Find the probability that an individual had between $0.80 and $1.00. Graph the situation, and shade in the area to be determined.
The finite population correction is most useful for which of the following? a. It adjusts the estimated mean when the sample size is a large fraction of the population size. b. It adjusts the standard error of the mean when the sample size is a small fraction of the population size. c. It adjusts the estimated mean when the sample size is a small fraction of the population size. d. It adjusts the standard error of the mean when the sample size is a large fraction of the population size.
Please state if the statement is correct or wrong and explain why. Statement 1. The sampling distribution of the sample mean with a sample size of 12 has a smaller standard error than that of the sampling distribution of the sample mean with a sample size of 13. Statement 2. Degrees of Freedom is one of the parameters of the normal distribution. Statement 3. A parameter is a function of a sample.
3.) A population has a mean of 300 and a variance of 80. If we get 160 samples from this population, what wili be the mean and standard deviation of the sampling distribution of sample mean? A.) Hg = 300 and og =0.53 B.) µg = 300 and og =0.71 C.) µg = 300 and og =6.32 D.) µg = 300 and og =80 %3D %3D
please answer quickly
In a population of a certain species of newt, the mean length of the newts is μ= 63 inches and the standard deviation is σ= 3.4 inches. You collect a random sample of n=16 newts. The bell curve below represents the distribution of these sample means. The scale on the horizontal axis is the standard error of the sampling distribution. Complete the indicated boxes, correct to two decimal places. mean of distribution= standard error= Note: The left box is 2 standard errors below the mean. The middle box is the mean. The right box is 2 standard errors above the mean.
In this problem, assume that the distribution of differences is approximately normal. Note: For degrees of freedom d.f. not in the Student's t table, use the closest d.f. that is smaller. In some situations, this choice of d.f. may increase the P-value by a small amount and therefore produce a slightly more "conservative" answer. I need help with sketchng the distribution, (d) and (e)
Solve part a,b and c of practice question #2. Please and thank you.
14:45. (a) For a normal distribution with mean u and standard deviation o, obtain the first and third quärtiles and also the quartile deviation. (b) For a normal distribution with mean 50 and s.d. 15, find Q, and Q3. dial. ao
A magazine claims that the mean amount spent by a customer at Burger Stop is greater than the mean amount spent by a customer at Fry World. The results for samples of customer transactions for the two fast food restaurants are shown below. At x = 0.01, can you support the magazine's claim? Assume the population variances are equal. Assume the samples are random and independent, and the populations are normally distributed. Complete parts (a) through (e) below. Burger Stop Fry World X₁ = $11.22 X₂ = $10.59 $₁ = $0.79 $2 = $0.64 n₂ = 10 n₁ = 12 (a) Identify the claim and state Ho and H₂. Which is the correct claim below? O A. "The mean amount spent by a customer at Burger Stop is greater than the mean amount spent by a customer at Fry World." OB. "The mean amount spent by a customer at Burger Stop is equal to the mean amount spent by a customer at Fry World." O c. "The mean amount spent by a customer at Burger Stop is not equal to the mean amount spent by a customer at Fry World." O D.…

Recommended textbooks for you

A First Course in Probability (10th Edition)

Probability

ISBN:

9780134753119

Author:

Sheldon Ross

Publisher:

PEARSON

A First Course in Probability

Probability

ISBN:

9780321794772

Author:

Sheldon Ross

Publisher:

PEARSON

A First Course in Probability (10th Edition)

Probability

ISBN:

9780134753119

Author:

Sheldon Ross

Publisher:

PEARSON

A First Course in Probability

Probability

ISBN:

9780321794772

Author:

Sheldon Ross

Publisher:

PEARSON

SEE MORE TEXTBOOKS