5.32* A candle that is 6.00 cm tall is standing 10 cm from a thin con- ave lens whose focal length is -30 cm. Determine the location of the mage and describe it in detail. Draw an appropriate ray diagram.

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Chapter1: Units, Trigonometry. And Vectors
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**Problem 5.32**

A candle that is 6.00 cm tall is standing 10 cm from a thin concave lens whose focal length is -30 cm. Determine the location of the image and describe it in detail. Draw an appropriate ray diagram.

### Solution Explanation

To find the image location and its properties, we will use the lens formula:

\[ 
\frac{1}{f} = \frac{1}{v} - \frac{1}{u} 
\]

where:
- \( f \) is the focal length of the lens (-30 cm, since the lens is concave),
- \( v \) is the image distance,
- \( u \) is the object distance (-10 cm, since the object is on the same side as the light's origin).

Substituting the known values and solving for \( v \) will give the image distance. 

### Ray Diagram

1. **Principal Axis**: Draw a horizontal line representing the principal axis.
2. **Lens**: Indicate the concave lens and mark the focal points on both sides of the lens.
3. **Object**: Place the object (candle) 10 cm from the lens on the principal axis.
4. **Ray 1 (Parallel Ray)**: Draw a ray parallel to the principal axis from the top of the object. After passing through the lens, this ray will diverge and appear to come from the focal point on the same side as the object.
5. **Ray 2 (Through Focal Point)**: Draw a ray from the top of the object through the focal point on the object side; after refraction, it becomes parallel to the principal axis on the opposite side.
6. **Ray Intersection**: The extension of these refracted rays will intersect on the object side, indicating the virtual image location.

### Image Characteristics
- **Type**: Virtual
- **Orientation**: Upright
- **Size**: Reduced (compared to the object)

This analysis helps in understanding the concept of image formation by concave lenses using ray diagrams.
Transcribed Image Text:**Problem 5.32** A candle that is 6.00 cm tall is standing 10 cm from a thin concave lens whose focal length is -30 cm. Determine the location of the image and describe it in detail. Draw an appropriate ray diagram. ### Solution Explanation To find the image location and its properties, we will use the lens formula: \[ \frac{1}{f} = \frac{1}{v} - \frac{1}{u} \] where: - \( f \) is the focal length of the lens (-30 cm, since the lens is concave), - \( v \) is the image distance, - \( u \) is the object distance (-10 cm, since the object is on the same side as the light's origin). Substituting the known values and solving for \( v \) will give the image distance. ### Ray Diagram 1. **Principal Axis**: Draw a horizontal line representing the principal axis. 2. **Lens**: Indicate the concave lens and mark the focal points on both sides of the lens. 3. **Object**: Place the object (candle) 10 cm from the lens on the principal axis. 4. **Ray 1 (Parallel Ray)**: Draw a ray parallel to the principal axis from the top of the object. After passing through the lens, this ray will diverge and appear to come from the focal point on the same side as the object. 5. **Ray 2 (Through Focal Point)**: Draw a ray from the top of the object through the focal point on the object side; after refraction, it becomes parallel to the principal axis on the opposite side. 6. **Ray Intersection**: The extension of these refracted rays will intersect on the object side, indicating the virtual image location. ### Image Characteristics - **Type**: Virtual - **Orientation**: Upright - **Size**: Reduced (compared to the object) This analysis helps in understanding the concept of image formation by concave lenses using ray diagrams.
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