3.8. Draw an impedance diagram for the electric power system as shown in Fig. 5.34, and all impedancesin per-unit on a 100 MVA base. Select 20 kV base voltage for generator. The three-phase power andline ratings are given below.G1 : 90 MVA, 20 kV, x = 0.09 puG2 : 90 MVA, 18 kV, x2T1 : 80 MVA, 20/200 kV, x = 0.16 puT2 : 80 MVA, 200/20 kV, x2 = 0.20 pu%3D= 0.09 puLine : 200 kV, xine = 120Load : 200 kV, S= (48 +j64)MVA.G,LineG,V LOADFig. 5.34: Single line diagram for problem 5.3.

As we have given : G1=90 MVA,20 kV,xG1=0.09 puG2=90 MVA,18 kV,xG2=0.09 puT1=80 MVA, 20/200…

5.3. Draw an impedance diagram for the electric power system as shown in Fig. 5.34, and all impedances in per-unit on a 100 MVA base. Select 20 kV base voltage for generator. The three-phase power anc line ratings are given below. G1: 90 MVA, 20 kV, xg1 G2 : 90 MVA, 18 kV, x = 0.09 pu T1: 80 MVA, 20/200 kV, xu = 0.16 pu T2 : 80 MVA, 200/20 kV, x2 = 0.20 pu Line : 200 kV, xine = 120 Load : 200 kV, S= (48 + j64)MVA. = 0.09 pu Line V LOAD Fig. 5.34: Single line diagram for problem 5.3.

5.3. Draw an impedance diagram for the electric power system as shown in Fig. 5.34, and all impedances in per-unit on a 100 MVA base. Select 20 kV base voltage for generator. The three-phase power anc line ratings are given below. G1: 90 MVA, 20 kV, xg1 G2 : 90 MVA, 18 kV, x = 0.09 pu T1: 80 MVA, 20/200 kV, xu = 0.16 pu T2 : 80 MVA, 200/20 kV, x2 = 0.20 pu Line : 200 kV, xine = 120 Load : 200 kV, S= (48 + j64)MVA. = 0.09 pu Line V LOAD Fig. 5.34: Single line diagram for problem 5.3.

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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