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5.3 The Second Law of Thermodynamics 1. a. Calculate the entropy change, AS° at 25°C. for the following reaction, universe CO (g) + 2H, (g) CH,OH() CO (g) H, (g) = CH,OH (1) = 127.2 J/mol-K 197.7 J/mol-K 130.7 J/mol-K Standard entropy, 'S° : %3D Standard enthalpy of formation, AH,: CO (g) = - 110.5 kJ/mol H, (g) = 0 CH,OH (1) = - 238.4 kJ/mol %3D b. From the calculated entropy change value, what can you conclude regarding the process?

5.3 The Second Law of Thermodynamics 1. a. Calculate the entropy change, AS° at 25°C. for the following reaction, universe CO (g) + 2H, (g) CH,OH() CO (g) H, (g) = CH,OH (1) = 127.2 J/mol-K 197.7 J/mol-K 130.7 J/mol-K Standard entropy, 'S° : %3D Standard enthalpy of formation, AH,: CO (g) = - 110.5 kJ/mol H, (g) = 0 CH,OH (1) = - 238.4 kJ/mol %3D b. From the calculated entropy change value, what can you conclude regarding the process?

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
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5.3 The Second Law of Thermodynamics 1. a. Calculate the entropy change, AS° for the following reaction, universe at 25°C. CO (g) + 2H, (g) CH,OH(1) - CO (g) H, (g) CH OH (1) = 127.2 J/mol-K Standard entropy, S°: 197.7 J/mol-K 130.7 J/mol-K Standard enthalpy of formation, AH,: - 110.5 kJ/mol CO (g) H, (g) CH,OH (1) = - 238.4 kJ/mol !! b. From the calculated entropy change value, what can you conclude regarding the process?
Transcribed Image Text:5.3 The Second Law of Thermodynamics 1. a. Calculate the entropy change, AS° for the following reaction, universe at 25°C. CO (g) + 2H, (g) CH,OH(1) - CO (g) H, (g) CH OH (1) = 127.2 J/mol-K Standard entropy, S°: 197.7 J/mol-K 130.7 J/mol-K Standard enthalpy of formation, AH,: - 110.5 kJ/mol CO (g) H, (g) CH,OH (1) = - 238.4 kJ/mol !! b. From the calculated entropy change value, what can you conclude regarding the process?
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