### Problem 5.29 - DC Circuit Analysis**Objective:** For the circuit in Figure P5.29, determine the voltages across capacitors \(C_1\) and \(C_2\), and the currents through inductors \(L_1\) and \(L_2\) under direct current (DC) conditions.### Circuit Description:The diagram depicts an electrical circuit consisting of two inductors, two capacitors, resistors, and a voltage source. The following are the key components and their values:1. Inductor \(L_1 = 2 \text{ H}\)2. Inductor \(L_2 = 6 \text{ H}\)3. Capacitor \(C_1 = 1 \, \mu\text{F}\)4. Capacitor \(C_2 = 2 \, \mu\text{F}\)5. Resistors: \(10 \, \Omega\), \(5 \, \Omega\), \(6 \, \Omega\), and \(4 \, \Omega\)6. Voltage Source: \(30 \text{ V}\)### Diagram Explanation:- The 30 V DC voltage source is connected in series with a \(10 \, \Omega\) resistor and inductor \(L_1\), which is followed by capacitor \(C_1\).- The circuit branches after the \(10 \, \Omega\) resistor. - One branch contains a \(5 \, \Omega\) resistor in series with capacitor \(C_2\). - The second branch has a \(6 \, \Omega\) resistor in series with inductor \(L_2 = 6 \, \text{H}\) and followed by a \(4 \, \Omega\) resistor.### Procedure for DC Analysis:1. **Steady-State Analysis for Capacitors:** - Under DC conditions, capacitors act as open circuits. - Therefore, no current will flow through branches containing capacitors \(C_1\) and \(C_2\). - The voltage across a capacitor in a steady-state is equal to the supply voltage if it is directly connected to the supply.2. **Steady-State Analysis for Inductors:** - Under DC conditions, inductors act as short circuits. - Hence, \(L_1\) and \(L_2\

Under dc condition the capacitor behaves as an open circuit and the inductor behaves as a short…

*5.29 For the circuit in Fig. P5.29, determine the voltages across C₁ and C₂ and the currents through L₁ and L2 under dc conditions. 10 Ω L₁ = 2 H C₁ = 1 µF 5Ω C₂=2 μF 6Ω + 30 V m L₂= 6 H Figure P5.29: Circuit for Problem 5.29. 4Ω

*5.29 For the circuit in Fig. P5.29, determine the voltages across C₁ and C₂ and the currents through L₁ and L2 under dc conditions. 10 Ω L₁ = 2 H C₁ = 1 µF 5Ω C₂=2 μF 6Ω + 30 V m L₂= 6 H Figure P5.29: Circuit for Problem 5.29. 4Ω

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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Concept explainers

Maximum power transfer theorem

A resistive load will consume maximum power from a network when the load resistance is equal to the resistance of the network as viewed from the open-circuit terminals, with all energy sources removed leaving only the internal resistances. Physicist Moritz von Jacobi introduced the maximum power transfer theorem in 1940. Therefore, this theorem is also known as Jacobi's law.

Question

### Problem 5.29 - DC Circuit Analysis

**Objective:**
For the circuit in Figure P5.29, determine the voltages across capacitors \(C_1\) and \(C_2\), and the currents through inductors \(L_1\) and \(L_2\) under direct current (DC) conditions.

### Circuit Description:
The diagram depicts an electrical circuit consisting of two inductors, two capacitors, resistors, and a voltage source. The following are the key components and their values:
1. Inductor \(L_1 = 2 \text{ H}\)
2. Inductor \(L_2 = 6 \text{ H}\)
3. Capacitor \(C_1 = 1 \, \mu\text{F}\)
4. Capacitor \(C_2 = 2 \, \mu\text{F}\)
5. Resistors: \(10 \, \Omega\), \(5 \, \Omega\), \(6 \, \Omega\), and \(4 \, \Omega\)
6. Voltage Source: \(30 \text{ V}\)

### Diagram Explanation:
- The 30 V DC voltage source is connected in series with a \(10 \, \Omega\) resistor and inductor \(L_1\), which is followed by capacitor \(C_1\).
- The circuit branches after the \(10 \, \Omega\) resistor.
- One branch contains a \(5 \, \Omega\) resistor in series with capacitor \(C_2\).
- The second branch has a \(6 \, \Omega\) resistor in series with inductor \(L_2 = 6 \, \text{H}\) and followed by a \(4 \, \Omega\) resistor.

### Procedure for DC Analysis:
1. **Steady-State Analysis for Capacitors:**
- Under DC conditions, capacitors act as open circuits.
- Therefore, no current will flow through branches containing capacitors \(C_1\) and \(C_2\).
- The voltage across a capacitor in a steady-state is equal to the supply voltage if it is directly connected to the supply.

2. **Steady-State Analysis for Inductors:**
- Under DC conditions, inductors act as short circuits.
- Hence, \(L_1\) and \(L_2\

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