5.17 Investigate the effect of using an op amp with CMRRdB = 100 dB on the output resis- tance of a Howland current pump made up of four perfectly matched 10-k$2 resistances. Except for CMRR, the op amp is ideal. R₁ IN↓ Ip4 M R₂ m

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### Investigating the Effect of Common Mode Rejection Ratio on Howland Current Pump Output

**Problem Statement:**

**5.17** Investigate the effect of using an op amp with a Common Mode Rejection Ratio (CMRR) of 100 dB on the output resistance of a Howland current pump made up of four perfectly matched 10-kΩ resistances. Except for CMRR, the op amp is considered ideal.

---

**Figure 5.7: Howland Current Pump Circuit**

The diagram represents a Howland current pump circuit. Below is a detailed explanation of its components:

- **Resistors:**
  - \( R_1 \) and \( R_2 \) are placed in series.
  - \( R_P \) (R subscript P) appears to be connected to the inverting input of the operational amplifier (op amp) and grounded at the other end.

- **Currents:**
  - \( I_N \) is the current entering the circuit near \( R_1 \).
  - \( I_P \) is the current flowing through \( R_P \) and into the inverting input of the op amp.

- **Operational Amplifier (Op Amp):**
  - The op amp shows traditional inverting and non-inverting inputs.
  - The inverting input is connected to \( R_2 \) while the non-inverting input is grounded.
  - The output \( V_O \) is taken from the output pin of the op amp.

The CMRR value impacts how the input voltage discrepancies affect the output. In this scenario, the focus is on understanding how a CMRR of 100 dB would influence the output resistance in such a configuration, considering the op amp is otherwise ideal.

---

This analysis is relevant for discussing precision in analog circuits, especially when designing systems requiring accurate current sources.
Transcribed Image Text:### Investigating the Effect of Common Mode Rejection Ratio on Howland Current Pump Output **Problem Statement:** **5.17** Investigate the effect of using an op amp with a Common Mode Rejection Ratio (CMRR) of 100 dB on the output resistance of a Howland current pump made up of four perfectly matched 10-kΩ resistances. Except for CMRR, the op amp is considered ideal. --- **Figure 5.7: Howland Current Pump Circuit** The diagram represents a Howland current pump circuit. Below is a detailed explanation of its components: - **Resistors:** - \( R_1 \) and \( R_2 \) are placed in series. - \( R_P \) (R subscript P) appears to be connected to the inverting input of the operational amplifier (op amp) and grounded at the other end. - **Currents:** - \( I_N \) is the current entering the circuit near \( R_1 \). - \( I_P \) is the current flowing through \( R_P \) and into the inverting input of the op amp. - **Operational Amplifier (Op Amp):** - The op amp shows traditional inverting and non-inverting inputs. - The inverting input is connected to \( R_2 \) while the non-inverting input is grounded. - The output \( V_O \) is taken from the output pin of the op amp. The CMRR value impacts how the input voltage discrepancies affect the output. In this scenario, the focus is on understanding how a CMRR of 100 dB would influence the output resistance in such a configuration, considering the op amp is otherwise ideal. --- This analysis is relevant for discussing precision in analog circuits, especially when designing systems requiring accurate current sources.
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