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5.00 Hz 10.0 V 0.00 V MHz 10 v + 1 +5V a b c d e . • P GENERATOR -234567 2= 2 www.www ಹ ಸ ಹ ಹ ಸ ದ ಸ = ಕ ೦ 1.00 s N 1.00 s

5.00 Hz 10.0 V 0.00 V MHz 10 v + 1 +5V a b c d e . • P GENERATOR -234567 2= 2 www.www ಹ ಸ ಹ ಹ ಸ ದ ಸ = ಕ ೦ 1.00 s N 1.00 s

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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A- Build the above circuit using TinkerCad, with the following values:

      R= 6KΩ.

     C= 19 uF

B- Change the frequency of the input source signal using the following values, and check the difference between the input and output signals on both oscilloscopes.
   f =  2 Hz, 10 Hz, 16 Hz, 20 Hz, 50 Hz.

Answer the following questions: 

1. What is the value of the cut-off frequency (fc) in the given filter in Hz?

2. If the value of the resistor is changed to be 19KΩ,  what should be the value of the capacitor (C) in uF to have the same cut-off frequency you found in the previous question? 

 

 What do you think the type of this filter?

a.Band Stop Filter (BSF)
b.High Pass Filter (HPF)

c.Low Pass Filter (LPF)

d.Band Pass Filter (BPF)

 

5.00 Hz 10.0 V 0.00 V MHz 10 v + 1 +5V a b c d e . • P GENERATOR -234567 2= 2 www.www ಹ ಸ ಹ ಹ ಸ ದ ಸ = ಕ ೦ 1.00 s N 1.00 s
Transcribed Image Text:5.00 Hz 10.0 V 0.00 V MHz 10 v + 1 +5V a b c d e . • P GENERATOR -234567 2= 2 www.www ಹ ಸ ಹ ಹ ಸ ದ ಸ = ಕ ೦ 1.00 s N 1.00 s
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